Sphere's Electric Potential HELP

[BuBbLeS01]

Sphere's Electric Potential...HELP!

Homework Statement

A 2.04-mm-diameter ball bearing has 8.710×10^9 excess electrons. What is the ball bearing�s potential?

Homework Equations

The Attempt at a Solution

V = (1/4*pi*Eo) * (Q/r)
Eo = 8.85 x 10^-12
Q = 1.6x10^-19 * 8.71x10^9
r = 0.00204/2
V = 12308.78 V

Can someone tell me what I am doing wrong?

 

[Ronnin]

Why are you multiplying your excess charge by Epsilon-not to get Q?

 

[BuBbLeS01]

nevermind I just got it...thanks though!

 

[Ronnin]

Great!