Spherical Harmonics: Why |m| ≤ l?

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SUMMARY

The discussion centers on the requirement that for spherical harmonics, the absolute value of m must be less than or equal to l, where both m and l are integers. This condition arises from the properties of angular momentum in quantum mechanics, specifically from the commutation relations of the angular momentum operators. The eigenvalue m corresponds to the z-component of angular momentum (Lz), while l relates to the total angular momentum (L^2). The mathematical justification is rooted in ensuring that the associated Legendre functions behave appropriately at the poles.

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  • Understanding of quantum mechanics, specifically angular momentum operators.
  • Familiarity with spherical harmonics and their mathematical representation.
  • Knowledge of Legendre polynomials and their properties.
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  • Study the commutation relations of angular momentum operators in quantum mechanics.
  • Explore the mathematical properties of associated Legendre functions.
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Students and professionals in physics, particularly those focusing on quantum mechanics, as well as mathematicians interested in the applications of spherical harmonics in physical systems.

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Homework Statement


Why is is the for physical applications of the spherical harmonics |m| must be less than or equal to l, with both being integers?

Homework Equations


Y(m,l)=exp(im phi)P{m,l}(cos theta)
Hopefully my notation is clear, if not please say.

The Attempt at a Solution


Well m must be integer so that the the exponential is single valued as we go through 2pi on the phi axis, and l must also be integer so that the associated Legendre equation is well behaved at the poles, but I'm not sure why we require |m| is less than or equal to l? I suppose it must be something to do with the behaviour of the P part of the solution but I can't see what.

Any hints/ help appreciated,
Thanks
 
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Well, it's possible to prove just from the commutation relations of the components of the angular momentum operator that m (the eigenvalue of Lz/hbar) must be less than or equal to l (where l(l+1) is the eigenvalue of L^2/hbar^2). Classically, Lz must be less than or equal to L^2, so this is sensible.

Edit: I meant to say that, classically, Lz^2 (not Lz) must be less than or equal to L^2.
 
Last edited:
Thanks
 

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