Spin of planets, bigger means faster?

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SUMMARY

The discussion centers on the relationship between a planet's size and its rotational speed, concluding that larger planets can spin faster due to their formation from larger clouds of material, which enhances their angular momentum. The data presented shows the equatorial speeds of various planets, with Jupiter at 45,600 km/h and Mercury at only 10.9 km/h. Factors such as tidal friction and historical impacts on planets like Mercury and Uranus also influence their current rotation rates. The concept of angular momentum conservation is crucial in understanding these dynamics.

PREREQUISITES
  • Understanding of angular momentum conservation
  • Familiarity with planetary formation processes
  • Basic knowledge of planetary rotation and speed measurements
  • Concepts of tidal friction and its effects on planetary rotation
NEXT STEPS
  • Research the effects of tidal friction on planetary rotation, specifically focusing on Mercury and Earth.
  • Explore the formation of planets from protoplanetary disks and its impact on angular momentum.
  • Investigate the historical impacts on planetary axes, particularly the case of Uranus.
  • Learn about the mathematical relationships between mass, radius, and angular momentum in celestial bodies.
USEFUL FOR

Astronomers, astrophysicists, and students of planetary science will benefit from this discussion, particularly those interested in planetary dynamics and rotational mechanics.

valdar
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Quick question, do bigger planet spin faster?
 
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Look up the data.
 
valdar said:
Quick question, do bigger planet spin faster?

In general, I don't think there's any relation.
 
You must look at planet formation to understand this issue. The short answer is yes.
 
I always thought that the smaller planets would rotate more rapidly than larger ones, under identical conditions of course. Much like a figure skater draws in his or her figure and seemingly rotates faster. However, I may be (and more than likely) am wrong. If someone could address this I would be interested to learn
 
Planet Speed at equator (km/h)
Mercury 10.9
Venus 6.5
Earth 1670
Mars 867
Jupiter 45600
Saturn 37000
Uranus 10900
Neptune 8460
Pluto 47

You would expect small planets to spin faster - from conservation of angular momentum

But larger planets were formed from larger clouds of stuff.
As stuff contracted, then because of conservation of angular momentum it speeded up, the bigger/faster the original cloud the faster it ended up. Of course if you took the existing planets and made each of them smaller - they would speed up even more.

Then there are effects that have happened since. Mercury's rotation is slowed by tidal friction with the sun so has a very slow speed (long day), the Earth's is slowed a little by friction with the moon.
Uranus probably got hit by something in the past - which is why it has a weird axis tilt.
Mars might also have been affected by whatever caused the asteroid belt.
 
mgb_phys said:
Planet Speed at equator (km/h)
Mercury 10.9
Venus 6.5
Earth 1670
Mars 867
Jupiter 45600
Saturn 37000
Uranus 10900
Neptune 8460
Pluto 47

You would expect small planets to spin faster - from conservation of angular momentum

But larger planets were formed from larger clouds of stuff.
As stuff contracted, then because of conservation of angular momentum it speeded up, the bigger/faster the original cloud the faster it ended up. Of course if you took the existing planets and made each of them smaller - they would speed up even more.

Then there are effects that have happened since. Mercury's rotation is slowed by tidal friction with the sun so has a very slow speed (long day), the Earth's is slowed a little by friction with the moon.
Uranus probably got hit by something in the past - which is why it has a weird axis tilt.
Mars might also have been affected by whatever caused the asteroid belt.


Very interesting. Thank you for providing this
 
A good way of comparing spin in stars is to compare angular momentum and mass in geometric units where-

a=J/mc

M=Gm/c^2

where

J=vmr\,k

where a is the spin parameter in metres, v is the equatorial rotation velocity, m is mass, r is the equatorial radius and k is the moment of inertia coefficient (0.4 for an idealized sphere of uniform density).

a/M produces a unitless figure between 0 and 1, the higher the number, the higher the spin. For the Sun (k=0.06), a/M=~0.188, for a 2.2 sol neutron star with a frequency of 1500 Hz (k=0.35), a/M=~0.488.

This doesn't appear so straightforward with planets as M works out considerably smaller than a but there should still be a way of comparing spin geometrically.EDIT:
In the case of planets, you could probably get away with just considering the results of a which is considered to be the amount of angular momentum per unit of mass (sometimes expressed as J/M). In this case, Jupiter is the clear winner and Mercury has the least 'spin' per unit of mass.
 
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