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A bee goes from its hive in a spiral path given in plane polar coordinates by
r = b*ekt , θ = ct,
where b, k, c are positive constants. Show that the angle between the velocity vector and the
acceleration vector remains constant as the bee moves outward. (Hint: Find v · a/va.)
attempts.
v=r[dot]r[hat]+(r)θ[dot]θ[hat]
a=(r[double dot]-rθ[dot]^2)r[hat]+(rθ[double dot]+2r[dot]θ[dot])θ[hat]
r[prime]=bke^kt
r[double prime]= bk^(2)e^kt
θ[prime]=c
I know that v · a/va = vacosθ/va = cosθ, but I am unsure what to do with this knowledge or where to go from here,
thanks guys
r = b*ekt , θ = ct,
where b, k, c are positive constants. Show that the angle between the velocity vector and the
acceleration vector remains constant as the bee moves outward. (Hint: Find v · a/va.)
attempts.
v=r[dot]r[hat]+(r)θ[dot]θ[hat]
a=(r[double dot]-rθ[dot]^2)r[hat]+(rθ[double dot]+2r[dot]θ[dot])θ[hat]
r[prime]=bke^kt
r[double prime]= bk^(2)e^kt
θ[prime]=c
I know that v · a/va = vacosθ/va = cosθ, but I am unsure what to do with this knowledge or where to go from here,
thanks guys