Telemachus
- 820
- 30
Homework Statement
I've got this problem on polar coordinates which says:
A particle moves along a plane trajectory on such a way that its polar coordinates are the next given functions of time:
r=0.833t^3+5t \theta=0.3t^2
Determine the module of the speed and acceleration vectors for this particle and its radius of curvature at the instant t=2s.
And I don't know how to solve the radius of curvature part.
For intrinsic coordinates I know that: \rho=\displaystyle\frac{v^2}{a_n}
Where a_n is the normal acceleration. Now how do I find the radius of curvature? do I have to take the trajectory to the intrinsic form?
For the first part I have that:
\dot r=v(t)=\dot r\vec{e_r}+r\dot \theta\vec{e_{\theta}}
v(2s)\approx{}10\hat{e_r}+20\hat{e_{\theta}}
\ddot r=a(t)=(\ddot r-r\dot \theta^2)\vec{e_r}+(r\ddot \theta+2 \dot r \dot \theta)\vec{e_{\theta}}
a(2s)\approx{}-10\hat{e_r}+46\hat{e_{\theta}}
From there I can get the modules, but I don't worry about that, I want to know how to find the radius of curvature at the point.
Bye there, and thanks for posting.