- #1
Telemachus
- 835
- 30
Homework Statement
I've got this problem on polar coordinates which says:
A particle moves along a plane trajectory on such a way that its polar coordinates are the next given functions of time:
[tex]r=0.833t^3+5t[/tex] [tex]\theta=0.3t^2[/tex]
Determine the module of the speed and acceleration vectors for this particle and its radius of curvature at the instant [tex]t=2s[/tex].
And I don't know how to solve the radius of curvature part.
For intrinsic coordinates I know that: [tex]\rho=\displaystyle\frac{v^2}{a_n}[/tex]
Where [tex]a_n[/tex] is the normal acceleration. Now how do I find the radius of curvature? do I have to take the trajectory to the intrinsic form?
For the first part I have that:
[tex]\dot r=v(t)=\dot r\vec{e_r}+r\dot \theta\vec{e_{\theta}}[/tex]
[tex]v(2s)\approx{}10\hat{e_r}+20\hat{e_{\theta}}[/tex]
[tex]\ddot r=a(t)=(\ddot r-r\dot \theta^2)\vec{e_r}+(r\ddot \theta+2 \dot r \dot \theta)\vec{e_{\theta}}[/tex]
[tex]a(2s)\approx{}-10\hat{e_r}+46\hat{e_{\theta}}[/tex]
From there I can get the modules, but I don't worry about that, I want to know how to find the radius of curvature at the point.
Bye there, and thanks for posting.