Spiraling Towards the Center: Solving the Orbit Equation

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SUMMARY

The discussion centers on solving the orbit equation, specifically the equation \(\frac{d^2}{d \theta^2} \frac{1}{r} = 0\), leading to the solution \(\frac{1}{r} = A \theta + B\). The user seeks clarification on how this solution indicates that a particle spirals towards the center. The original orbit equation, \(\frac{d^2}{d \theta^2} \frac{1}{r} + (1 - \frac{\mu k}{l^2}) \frac{1}{r} = 0\), describes motion under effective potential conditions. The user expresses confusion regarding the implications of their derived equation in relation to the particle's trajectory.

PREREQUISITES
  • Understanding of differential equations, particularly second-order equations
  • Familiarity with orbital mechanics and effective potential concepts
  • Knowledge of polar coordinates and their applications in physics
  • Basic grasp of mathematical constants and parameters such as \(\mu\), \(k\), and \(l\)
NEXT STEPS
  • Study the derivation and implications of the effective potential in orbital mechanics
  • Learn about the physical interpretation of spiraling motion in polar coordinates
  • Explore advanced topics in celestial mechanics, focusing on perturbation theory
  • Review the mathematical techniques for solving second-order differential equations
USEFUL FOR

This discussion is beneficial for physics students, mathematicians, and researchers interested in orbital dynamics and the mathematical modeling of motion in gravitational fields.

UrbanXrisis
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So i solved the orbit equation:

[tex]\frac{d^2}{d {\theta} ^2} \frac{1}{r} =0[/tex]

the solution is:

[tex]\frac{1}{r} = A \theta +B[/tex]

I am supposed to concude that this particle will sprial towards the center but I don't see that through this equation. could someone explain this to me? thanks
 
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the original equation is:

[tex]\frac{d^2}{d {\theta} ^2} \frac{1}{r} + (1- \frac{ \mu k}{l^2}) \frac{1}{r} =0[/tex]

describing the motion when the effective porential = 0, i get

[tex]\frac{d^2}{d {\theta} ^2} \frac{1}{r} =0[/tex]

so i was wondering how [tex]\frac{1}{r} = A \theta +B[/tex] tells me that I am sprial towards the center?
 

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