Spivak's Calculus Ch.2 Problem 2(i)

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SUMMARY

The discussion focuses on deriving a formula for the sum of the first n odd numbers, represented as Σ(2i-1) = 1 + 3 + 5 + ... + (2n-1). The key hint provided is to relate this sum to the sum of the first 2n natural numbers, S = 1 + 2 + ... + 2n. By analyzing the difference S - Y, where Y is the sum of the odd numbers, participants are guided to find a connection that leads to the solution. The insights shared culminate in a clearer understanding of how to express S - Y in terms of n.

PREREQUISITES
  • Understanding of summation notation and series
  • Familiarity with arithmetic series and their formulas
  • Basic algebraic manipulation skills
  • Knowledge of mathematical induction (for proving the formula)
NEXT STEPS
  • Study the formula for the sum of the first n natural numbers: S = n(n + 1)/2
  • Explore the concept of mathematical induction to prove formulas for series
  • Investigate the relationship between odd and even numbers in summation
  • Practice deriving formulas for other series, such as Σ(i^2) and Σ(i^3)
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Students studying calculus, mathematics educators, and anyone interested in understanding series and summation techniques in mathematical analysis.

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Homework Statement


Find a formula for Σ(2i-1) = 1+3+5+...+(2n-1)

Hint: What does the expression have to do with 1+2+3+...+2n?

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The Attempt at a Solution


I have tried to solve this on my own for about a day now, and I am having trouble understanding the significance of the hint. I don't want an answer, just advice on how to connect the hint and the original expression.[/B]
 
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Hint: let ##S = 1 + 2 + ... + 2n## and ##Y = 1 + 3 + 5 + ... + (2n - 1)##

Then what is ##S - Y##?
 
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axmls said:
Hint: let ##S = 1 + 2 + ... + 2n## and ##Y = 1 + 3 + 5 + ... + (2n - 1)##

Then what is ##S - Y##?

Also: how can you find ##S-Y## in terms of ##n##?
 
Last edited:
Thanks guys, i finally had an epiphany earlier today with your hints.
 
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