(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Part a.) You launch a 0.5 kg water balloon with a spring cannon in order to his someone 20m away. The spring in the cannon has a spring constant of 350 N/m. The spring cannon fires the balloon at a 30 degree angle with respect to the ground. What is the initial velocity necessary for the balloon to travel 20 meters?

Part b.) How much does the spring need to be compressed in order to achieve this initial velocity? Assume that 5 joules of heat is lost as the spring expands.

2. Relevant equations

F_{net}= F_{spring}- lwl = ma

sohcahtoa

*something for energy loss*

3. The attempt at a solution

Part a.) V initial was found to be 14.09 m/s

Part b.)

First I determined the lwl parallel be 30sin 4.9=2.45N

F_{net}= F_{spring}- lwl = ma

=k[tex]\Delta[/tex]x - lwl = ma

=350 x - 2.45 = 2.45

350x = 4.90

x=.014m

x-1.4cm

I have found that the spring compression would need to be 1.4cm to launch a .5kg ball 20 meters. However, this sounds small to me. Am I missing a force on the spring? I thought about including power, but I do not have the acceleration of the ball leaving the spring.

Also, I am not sure how to subtract 5 joules of energy due to heat loss.

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# Homework Help: Spring cannon, initial velocity, and compression

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