Spring cannon, initial velocity, and compression

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a spring cannon used to launch a water balloon. The problem includes calculating the initial velocity required for the balloon to travel a distance of 20 meters and determining the necessary compression of the spring, taking into account energy losses due to heat.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the calculation of initial velocity and spring compression, with some questioning the accuracy of the initial velocity found by the original poster. There are discussions about using conservation of energy to relate the potential energy of the spring to the kinetic energy of the balloon, along with considerations of energy loss.

Discussion Status

The conversation is active, with participants sharing different approaches and questioning each other's calculations. Some guidance on using conservation of energy has been suggested, but there is no explicit consensus on the correct values or methods yet.

Contextual Notes

Participants note the presence of energy loss (5 joules) and express uncertainty about the forces involved in the calculations. There is also a mention of the need to find acceleration to clarify the net force used in the calculations.

fischelr
Messages
1
Reaction score
0

Homework Statement


Part a.) You launch a 0.5 kg water balloon with a spring cannon in order to his someone 20m away. The spring in the cannon has a spring constant of 350 N/m. The spring cannon fires the balloon at a 30 degree angle with respect to the ground. What is the initial velocity necessary for the balloon to travel 20 meters?

Part b.) How much does the spring need to be compressed in order to achieve this initial velocity? Assume that 5 joules of heat is lost as the spring expands.


Homework Equations



Fnet = Fspring - lwl = ma
sohcahtoa
*something for energy loss*

The Attempt at a Solution



Part a.) V initial was found to be 14.09 m/s

Part b.)
First I determined the lwl parallel be 30sin 4.9=2.45N

Fnet = Fspring - lwl = ma
=k[tex]\Delta[/tex]x - lwl = ma
=350 x - 2.45 = 2.45
350x = 4.90
x=.014m
x-1.4cm


I have found that the spring compression would need to be 1.4cm to launch a .5kg ball 20 meters. However, this sounds small to me. Am I missing a force on the spring? I thought about including power, but I do not have the acceleration of the ball leaving the spring.

Also, I am not sure how to subtract 5 joules of energy due to heat loss.
 
Physics news on Phys.org
For part a, I did not get 14.09 m/s, can you post how you got that answer?

For part b, you could use conservation of energy here. But resultant force or 'ma' would not be 2.45 N, you'd need to find the acceleration.
 
On part B would it not simply be the potential energy of the spring = to the kinetic energy plus heat?

so .5(350)x^2 = .5(.5)14.09^2 + 5

x^2 = 54.6/175

x= .56 m
 
Yes that would be correct to do.
 
would a velocity of 15.04 be correct for this?
 
Yes that should be the initial velocity.
 
what equation did you use to get a velocity of 15.04? Thanks!
 
stephjuly28 said:
what equation did you use to get a velocity of 15.04? Thanks!

The better question is what did you use to get 14.09 m/s?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
17
Views
7K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 3 ·
Replies
3
Views
14K
Replies
15
Views
11K
Replies
5
Views
2K
Replies
4
Views
2K