Spring compression with masses in motion

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SUMMARY

The discussion centers on calculating the maximum compression of a spring during a collision between two blocks, where block m1 (2.5 kg) moves at 12 m/s and block m2 (6.2 kg) moves at 3.7 m/s. The conservation of momentum is applied to find the final velocity (vf) of the combined masses at maximum compression using the equation m1v1 + m2v2 = (m1 + m2)vf. The kinetic energy change of m1 is equated to the work done on the spring, leading to the equation 0.5m1vf² - 0.5m1v1² = 0.5kx², where k is the spring constant (1100 N/m). The user encounters issues with negative values when solving for x, indicating a misunderstanding in the application of energy conservation principles.

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scavok
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https://chip.physics.purdue.edu/protected/Halliday6Mimg/h10p33.jpg
A block of mass m1 = 2.5 kg slides along a frictionless table with a speed of 12 m/s. Directly in front of it, and moving in the same direction, is a block of mass m2 = 6.2 kg moving at 3.7 m/s. A massless spring with spring constant k = 1100 N/m is attached to the near side of m2, as shown in figure above. When the blocks collide, what is the maximum compression of the spring?

There's just too much going on here and I don't know where I'm going on wrong.

m1v1 + m2v2 = (m1+m2)vf
vf=velocity of both masses at the point where maximum compression is reached.

Is this correct?

If so, then the change in kinetic energy of mass m1 equals the work done on mass m1 by the spring:
.5m1vf2-.5m1v12=.5kx2

But this gets me a negative value, which it should since it is losing velocity, but I can't take the square root of a negative value which I need to do when solving for x. This makes me think I'm doing something wrong.
 
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Apply conservation of energy: state that the sum of initial kinetic energies of the blocks equals their sums at the point of compression plus the energy stored in the spring.
 
scavok said:
https://chip.physics.purdue.edu/protected/Halliday6Mimg/h10p33.jpg
A block of mass m1 = 2.5 kg slides along a frictionless table with a speed of 12 m/s. Directly in front of it, and moving in the same direction, is a block of mass m2 = 6.2 kg moving at 3.7 m/s. A massless spring with spring constant k = 1100 N/m is attached to the near side of m2, as shown in figure above. When the blocks collide, what is the maximum compression of the spring?

There's just too much going on here and I don't know where I'm going on wrong.

m1v1 + m2v2 = (m1+m2)vf
vf=velocity of both masses at the point where maximum compression is reached.

Is this correct?

If so, then the change in kinetic energy of mass m1 equals the work done on mass m1 by the spring:
.5m1vf2-.5m1v12=.5kx2

But this gets me a negative value, which it should since it is losing velocity, but I can't take the square root of a negative value which I need to do when solving for x. This makes me think I'm doing something wrong.

If you are comfortable with it, a way to simplify the problem would be use center of mass coordinates, do the spring problem, then convert back to "lab" coordinates.

-Dan
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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