Spring Dynamic Kinematics - acceleration

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SUMMARY

The discussion centers on the confusion surrounding the equation for acceleration in the context of Spring Dynamic Kinematics, specifically the equation a = 400 - kx. Participants clarify that in this scenario, k does not represent the spring constant but rather a constant in the linear relationship between acceleration (a) and displacement (x). The omission of mass from the equation is justified by the fact that mass is not relevant to the specific problem being addressed. This distinction is crucial for understanding how forces and acceleration are represented in kinematic equations.

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  • Familiarity with Newton's laws of motion
  • Knowledge of standard physics equations related to forces and acceleration
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Haizakokaru
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Homework Statement



2.26_zpsrtzbm2wr.png

Homework Equations


Standard physics equations before forces are introduced into kinematics
U1L6a1.gif


The Attempt at a Solution



I simply looked at Chegg and could not figure out how

a = 400 - kx

when logic dictates that

a = 400 - kx/m

, since this is possibly a sum of forces. Otherwise, it is lost to me how

F= -kx

is suddenly an acceleration quantity. Could someone explain that one line? Everything makes sense save for how

kx

stands alone in an acceleration equation. A classmate of mine who took this class before explained to me that in my dynamics class, mass is dropped from the equation when mass is not relevant to the question. However, he could not describe the reasoning behind it, so I was left somewhat unsatisfied by the answer.[/B]
 
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In the solution, ##k## does not represent the spring constant. It just represents a constant in the linear relation between ##a## and ##x##.
 
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