High school physics problem involving a spring slingshot

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Homework Help Overview

The discussion revolves around a physics problem involving a spring slingshot on an inclined plane. The original poster seeks to determine how much to stretch the spring to hit a target, given various parameters such as the mass of the spring, the angle and height of the incline, the spring constant, and the distance to the target.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of energy equations and kinematic equations to relate the spring's stretch to the initial velocity and distance to the target. There is an emphasis on the challenge of having multiple variables, particularly the stretch of the spring itself, which complicates the calculations.

Discussion Status

Some participants suggest expressing the speed and distance as functions of the unknown variable (the spring extension) to facilitate solving the problem. There is acknowledgment of the need for more information to proceed effectively, and participants are exploring different methods to relate the variables involved.

Contextual Notes

Participants note that the stretch of the spring is a variable that must be determined to calculate the work done by the spring, which adds complexity to the problem. There is a focus on ensuring that time is accounted for in the kinematic equations used.

Kailford
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Homework Statement


For a grade 12 physics project we have to stretch a spring along an inclined plane and then let go so that it hits a target. I know the mass of the spring, the angle of the incline, the height of the incline (how high the front of the spring would be off the ground before launching) the spring constant, and the distance from the target. Using this information, I need to figure out how much to stretch the spring to hit the target. How do I do this?

Homework Equations


Es = (1/2)kx^2
Eg = mgh
Ek = 1/2mv^2
Fs = kx
Fnet = ma
d = 1/2(v1 + v2)t
v2 = v1 + at
d = v1t + (1/2)at^2
d = v2t - (1/2)at^2
v2^2 = v1^2 + 2ad

The Attempt at a Solution


I have tried splitting the spring force into x and y components and then using that to find the acceleration, but that simple results in 2 variables (the acceleration and the amount the spring needs to be stretched). I have also tried using the different kinematic equations to try and find the velocity so that I can use it to find x by setting (1/2)kx^2 equal to (1/2)mv^2, but all of those equations either have v, t, or both as variables, and I am unable to solve for those.
 
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The steps you're doing seem okay, you just need more info. You could try figuring out the initial velocity by seeing how much work the spring does up until the point of release (and then applying the work KE thm)
 
Brian T said:
The steps you're doing seem okay, you just need more info. You could try figuring out the initial velocity by seeing how much work the spring does up until the point of release (and then applying the work KE thm)
Thanks Brian! I am at a loss as to how I would do that, though. As far as I know I need to know how much the spring is stretched to determine the work of the spring before release, but the stretch of the spring is one of my variables.
 
Kailford said:
Thanks Brian! I am at a loss as to how I would do that, though. As far as I know I need to know how much the spring is stretched to determine the work of the spring before release, but the stretch of the spring is one of my variables.
You can follow that line, expressing the speed as a function of the unknown variable x (the initial spring extension). From there, obtain the distance as a function of x, and see what x gives the desired distance.
Kailford said:
I have also tried using the different kinematic equations to try and find the velocity
That's the way I'd do it, working backwards. Remember you can write kinematic (SUVAT) equations for vertical and horizontal. They share the time variable, so you can eliminate that between them. That should give you enough information.
The trick with SUVAT equations is to pick the one that involves the four variables of interest. Since you need to set the times equal, you'll want t involved in each. Post some attempt.
 

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