Spring length hanging down and horizontal

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A spring is longer when hanging down vertically compared to being horizontal due to the force of gravity acting on its mass, which causes it to stretch more. The discussion raises questions about whether the entire mass of the spring or just the portion below the equilibrium point contributes to this stretch. It is suggested that each coil of the spring bears the weight of the coils above it, leading to maximum stretching at the top. Additionally, the equilibrium point is noted to shift as the spring stretches under its own weight. Understanding these dynamics is crucial for analyzing spring behavior in different orientations.
dav1d
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Homework Statement



is a spring longer hanging down or horizontal

Homework Equations





The Attempt at a Solution


i think that the spring is longer hanging down because then its own mass contributes to the force of gravity, making it stretch more.
 
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That is correct. When vertical, its own weight contributes to its stretch.
 
correct.
 
LawrenceC said:
That is correct. When vertical, its own weight contributes to its stretch.

Would it be the springs entire mass? Or just the part under the equilibrium?
 
dav1d said:
Would it be the springs entire mass? Or just the part under the equilibrium?

if it was only the part under the equilibrium then half of the spring would be stretched and half would be uncompressed right?
Each coil on the spring weights any coils above it. so you should have the most stretching at the very top, I think.
 
dacruick said:
if it was only the part under the equilibrium then half of the spring would be stretched and half would be uncompressed right?
Each coil on the spring weights any coils above it. so you should have the most stretching at the very top, I think.

But doesn't the equilibrium point move as the spring stretches?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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