Block dropped onto spring: finding maximum compression

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dorkymichelle
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Homework Statement



A block of mass m = 3.5 kg is dropped from height h = 81 cm onto a spring of spring constant k = 2220 N/m (Fig. 8-37). Find the maximum distance the spring is compressed.

Homework Equations



Pe(spring) = 1/2kx2
Pe(gravity)=mgh
Ke = 1/2mv2

The Attempt at a Solution



so far, i got mgh+1/2mvi2 =1/2mvf2 = 1/2kx2

because the energy used to compress the spring is the amount of energy from the end of the drop.
but I don't have initial velocity or final velocity. or can i use 0 as final velocity at the point that the object hits the spring..
 

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dorkymichelle said:

Homework Statement



A block of mass m = 3.5 kg is dropped from height h = 81 cm onto a spring of spring constant k = 2220 N/m (Fig. 8-37). Find the maximum distance the spring is compressed.

Homework Equations



Pe(spring) = 1/2kx2
Pe(gravity)=mgh
Ke = 1/2mv2

The Attempt at a Solution



so far, i got mgh+1/2mvi2 =1/2mvf2 + 1/2kx2

because the energy used to compress the spring is the amount of energy from the end of the drop.
but I don't have initial velocity or final velocity. or can i use 0 as final velocity at the point that the object hits the spring..
The block is dropped from rest, and it ends up momentarily at rest when the spring is fully compressed, not when it first hits the spring. You need to change your PE term to account for the extra height due to the spring displacement in its fully compressed position.
 
so kinetic initial and kinetic final would both be 0
changing my PE(gravity) term to include the compressed spring,
would the equation I need be mg(h+x) = 1/2kx^2 ? and solve for x to be the length the spring compresses?