Spring potential energy problem

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Homework Help Overview

The problem involves a block of mass 3.5 kg dropped from a height of 81 cm onto a spring with a spring constant of 2220 N/m. The objective is to find the maximum distance the spring is compressed.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of energy principles, considering potential energy from gravity and spring potential energy. There is uncertainty regarding the initial and final velocities and how to account for the spring's compression in the energy equations.

Discussion Status

Some participants have provided guidance on adjusting the potential energy terms to include the spring's displacement. There is an acknowledgment of the need to clarify the conditions at which the block is momentarily at rest.

Contextual Notes

Participants are navigating the implications of energy conservation and the definitions of potential and kinetic energy in the context of the spring's compression. There is a focus on ensuring all relevant heights are accounted for in the energy equations.

dorkymichelle
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Homework Statement



A block of mass m = 3.5 kg is dropped from height h = 81 cm onto a spring of spring constant k = 2220 N/m (Fig. 8-37). Find the maximum distance the spring is compressed.

Homework Equations



Pe(spring) = 1/2kx2
Pe(gravity)=mgh
Ke = 1/2mv2

The Attempt at a Solution



so far, i got mgh+1/2mvi2 =1/2mvf2 = 1/2kx2

because the energy used to compress the spring is the amount of energy from the end of the drop.
but I don't have initial velocity or final velocity. or can i use 0 as final velocity at the point that the object hits the spring..
 

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dorkymichelle said:

Homework Statement



A block of mass m = 3.5 kg is dropped from height h = 81 cm onto a spring of spring constant k = 2220 N/m (Fig. 8-37). Find the maximum distance the spring is compressed.

Homework Equations



Pe(spring) = 1/2kx2
Pe(gravity)=mgh
Ke = 1/2mv2

The Attempt at a Solution



so far, i got mgh+1/2mvi2 =1/2mvf2 + 1/2kx2

because the energy used to compress the spring is the amount of energy from the end of the drop.
but I don't have initial velocity or final velocity. or can i use 0 as final velocity at the point that the object hits the spring..
The block is dropped from rest, and it ends up momentarily at rest when the spring is fully compressed, not when it first hits the spring. You need to change your PE term to account for the extra height due to the spring displacement in its fully compressed position.
 
so kinetic initial and kinetic final would both be 0
changing my PE(gravity) term to include the compressed spring,
would the equation I need be mg(h+x) = 1/2kx^2 ? and solve for x to be the length the spring compresses?
 

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