Spring Question? How much does the block move?

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The discussion centers on the application of Hooke's Law to determine the displacement of a spring when different weights are applied. The weights W1 (110 N) and W2 (240 N) are used to establish a system of equations to solve for the spring constant k. The correct formula for the force exerted by the spring is F = -k*x, which is essential for calculating the displacement accurately. The user initially misapplied the work-energy principle, leading to incorrect results regarding the spring's displacement and the weight of the third package.

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A spring with a pointer attached is hanging next to a scale marked in millimeters. Three different packages are hung from the spring. W1 is 110 N, and hangs 40mm from the spring, W2 is 240N and hangs 60mm from the spring W3 is x N and hangs 30 mm from the springWhat mark on the scale will the pointer indicate when no package is hung from the spring?

What is the weight W of the 3rd package?

W = -1/2k(x22-x12)

One thing I wasn't sure about was this equation--are x1 and x2 in the correct order here because you're looking at the work done to stretch a spring?

3. I figured out that I had to create a system of equations from the two given weights, 110 N and 240 N, using the equation above. After converting mm to meters, I got two equations--

14.4 = -0.0018k + 0.5kx12
4.4 = -0.0008k + 0.5x12

I solved for k, got -10,000, and plugged back in, and got a length of 26.8 m--is that right? Because my online homework thing tells me I'm wrong...
 
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I think you have the wrong equation. The problem is about Forces, not Work.

Consider using F = -k*x
 

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