(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A mass m is resting at equilibrium suspended from a vertical spring of natural length L and spring constant K inside a box.

The box begins accelerating upward with acceleration a. How much closer does the equilibrium position of the mass move to the bottom of the box?

2. Relevant equations

f=kx

f=ma

3. The attempt at a solution

so this is my f=ma statement

kx-mg=ma

then i solved for x to get x= m(a+g) / k

but this answer is wrong and the correct answer is

ma / k

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# Spring system inside an accelerating box

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