Standard deviation and average value

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SUMMARY

The discussion centers on calculating the average value and standard deviation of five measurements of an object's height, which are 11.25 cm, 11.20 cm, 11.22 cm, 11.18 cm, and 11.25 cm. The average value calculated is 11.22 cm, and the standard deviation is determined to be 0.03 cm. However, the correct answer according to the textbook is B, h = (11.22 ± 0.04) cm, as the range of values indicates that the smallest measurement (11.18 cm) falls within this range. This highlights the importance of considering the range of measurements rather than solely relying on standard deviation.

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Homework Statement


Students measured an object 5 times, and got the results 11,25 cm, 11,20 cm, 11,22 cm, 11,18 cm i 11,25 cm. The height of this object is:

A. h = (11,22 ± 0,03) cm
B. h = (11,22 ± 0,04) cm
C. h = (11,25 ± 0,07) cm
D. h = (11,25 ± 0,03) cm

Homework Equations


Standard deviation and average value formulas.

The Attempt at a Solution



I calculated the average value (11.22) and the standard deviation (0.03), so the answer should be A. But in the book, B is the correct answer. Am I missing something here?
 
Last edited:
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This question does NOT ask for standard deviation and has nothing to do with standard deviation. It is true that the average is 11,22. The largest data value, 11,25= 11,22+ ,03 but the smallest is 11,18= 11,22- 0,04. All those numbers lie in the range 11,22\pm 0,04
 
Thanks, i didn't know about that.


SOLVED
 

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