http://highered.mheducation.com/olcweb/cgi/pluginpop.cgi?it=jpg::::::/sites/dl/free/0023654666/650262/Standard_Reduction_Potential_19_01.jpg::Standard reduction potentials The voltage is slightly different in my textbook. The questions I am trying to answer involve getting both half reactions and adding up the volts. The problem I am not getting the half reactions. here are the questions s= solid e- = electrons Cr(s) + 3AgCl(s) CrCl3(aq) + 3Ag(s) <---> One of the half reactions I get and the other I don't. Cr>Cr3+ + 3e = -.744 (.744 in my text) Cr3+(aq) + 3e-<>Cr(s) = .744V Now this is where I have trouble. I think it would be Ag+ (aq) + e- <> Ag(s) but the problem is the half reaction when I write is this. 3Agcl(s)+e->3AG(s) Because of the nature of reaction I would eliminate the moles and the cl which gives Ag+ (s) + e- <> Ag(s). This is very similar but there solid where there is an "aq" How is this possible question 2) Cl2+ 2Br> 2Cl- +Br2 two half reactions e- + Cl2<> 2Cl- the closet half reaction in my book is 2e- + Cl2 <> 2Cl- clearly there is a "2e-" Did I assign oxidation numbers wrong. Again I get for the other half reaction I get 2Br(-)<>br2+e- and it should be br2+ 2e<>2Br Also why do sometimes you remove the moles like ex 1 and ex 2 you keep the moles in the equation? Can someone answer this by doing the question and posting a picture of the equation and the work so I can understand. Please tell me if this very messy and I will rewrite it, Thanks for your help.