Standing sound waves created in a pipe, question about resonances

[helpmeplz!]

Hey guys i have a question for my lab report that i can't solve. We did a lab where we had a pipe and produced sound resonance in there, using a generator to vary the frequencies and we recorded our data.

the general formula is for the closed pipe, fn= n (v/4L) and wavelength= 4L/n.

The question is, explain why there are 3 cases of resonance when f= 500 hz, 4 cases of resonance when f= 700 hz and 6 cases of resonance when f= 1000 hz.

the length of the pipe was around 1 metre.

 

[rl.bhat]

Hi helpmeplease!, welcome to PF.
In a closed pipe, resonance occurs when the length of pipe is λ/4, 3λ/4, 5λ/4, and so on.
Length of the pipe is nearly one meter. If you take the velocity of the sound at temperature as 340 m/s, what is the wavelength of 500 Hz sound? Then see how many λ/4 lengths fit in one meter.