Standing Wave Wavelengths on 12m Rope: 2m, 1m & 5.5m

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The discussion focuses on determining possible standing wave wavelengths on a 12-meter rope secured at both ends, with established wavelengths of 2 meters and 1 meter. The key conclusion is that the wavelengths must be integer multiples of half the wavelength, leading to valid wavelengths of 2m, 1m, and others derived from this principle. The incorrect option identified is 67 cm, as it does not satisfy the condition of being an integer multiple of half a wavelength. The calculations confirm that only specific lengths can produce standing waves on the rope.

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If two wavelengths of standing waves on a 12 meter rope secured at both ends are 2 meters and 1 meter, which of the following could not be a standing wave wavelength on the same rope with the same tension?


Choices are: 4m, 2.5m, 1.5m, 67cm


12-2 =10, so 1\2 would be 5 and 12-1 = 11, so 1\2 = 5.5. I am rationalizing that 67 cm is not possible.
 
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I don't understand your calculations, and your answer is incorrect. Could you show your reasoning?

In order for there to be a standing wave, the rope's length must be an integer multiple of half a wavelength. If you don't see why, try drawing a diagrams of the first few harmonics, remembering that the ends of the rope must be nodes. So, which of the wavelengths satisfy this requirement?
 
I am still confused. I do not know what numbers to use from the problem into the equation.
 

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