Standing waves and banjo string

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A banjo string measuring 36.0 cm oscillates in a standing wave pattern, resonating at a fundamental frequency of 250 Hz. The tension in the string is to be calculated, given that 80.0 cm of the string has a mass of 0.75 grams. Key equations discussed include the relationship between wave velocity, tension, and linear mass density (μ). Participants clarified that for the fundamental frequency, the wavelength (λ) is twice the length of the vibrating portion of the string. The conversation emphasizes the importance of correctly identifying the length of the string used in calculations, particularly when transitioning between fundamental and overtone frequencies.
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1. A banjo string 36.0 cm long oscillates in a standing wave pattern. It resonates in its
fundamental mode at a frequency of 250 Hz. What is the tension in the string if 80.0 cm of the
string has a mass of 0.75 grams?



Homework Equations



k=2pi/lamda
velocity=sqrt(F_tension/miu)
miu=m/l
w=2pif

The Attempt at a Solution


v=sqrt(F_t/miu)
solved for miu and plugged into equation: 7.5*10^-4/.8
v=lamdaf
L=lamda/2
--> v=2Lf
v=2(.8)(250)
then equated both equations

i think i got confused with which length to use
 
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I think your work is ok.

Yes - mu =m/L and for fundamental frequency lambda = 2L.
 
I'm not sure when to use the length of the banjo string (36cm) :[
 
When the string is vibrating in its first overtone, i.e. its second harmonic, then the length of string will be the wavelength.
 
thank u. my answer is still incorrect... i would appreciate any more help. thank you
 
grzz said:
I think your work is ok.

Yes - mu =m/L and for fundamental frequency lambda = 2L.

May I correct my own contribution above.

mu = m/L where L = 0.80m but lambda = 2 x 0.36 since this is the length which is oscillating.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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