Standing waves and banjo string

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving standing waves on a banjo string, specifically focusing on the fundamental mode of oscillation and the calculation of tension based on given parameters such as frequency and mass of the string.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between the length of the string, mass, and frequency, with some attempting to clarify the correct application of formulas related to wave properties. Questions arise regarding which length to use in calculations and the implications of different modes of vibration.

Discussion Status

Some participants express uncertainty about the application of the string's length in the context of the fundamental frequency and overtone modes. There is acknowledgment of the original poster's attempts, and while some guidance has been offered, there is no clear consensus on the correct approach yet.

Contextual Notes

Participants are navigating the complexities of wave mechanics, particularly in distinguishing between the fundamental frequency and higher harmonics, while also considering the mass distribution along the string.

phyzeek
Messages
3
Reaction score
0
1. A banjo string 36.0 cm long oscillates in a standing wave pattern. It resonates in its
fundamental mode at a frequency of 250 Hz. What is the tension in the string if 80.0 cm of the
string has a mass of 0.75 grams?



Homework Equations



k=2pi/lamda
velocity=sqrt(F_tension/miu)
miu=m/l
w=2pif

The Attempt at a Solution


v=sqrt(F_t/miu)
solved for miu and plugged into equation: 7.5*10^-4/.8
v=lamdaf
L=lamda/2
--> v=2Lf
v=2(.8)(250)
then equated both equations

i think i got confused with which length to use
 
Physics news on Phys.org
I think your work is ok.

Yes - mu =m/L and for fundamental frequency lambda = 2L.
 
I'm not sure when to use the length of the banjo string (36cm) :[
 
When the string is vibrating in its first overtone, i.e. its second harmonic, then the length of string will be the wavelength.
 
thank u. my answer is still incorrect... i would appreciate any more help. thank you
 
grzz said:
I think your work is ok.

Yes - mu =m/L and for fundamental frequency lambda = 2L.

May I correct my own contribution above.

mu = m/L where L = 0.80m but lambda = 2 x 0.36 since this is the length which is oscillating.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
1K
Replies
13
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
13K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K