Star to black hole same mass/gravity?

  • Context: Undergrad 
  • Thread starter Thread starter narrator
  • Start date Start date
  • Tags Tags
    Black hole Hole Star
Click For Summary
SUMMARY

When a star collapses into a black hole, it typically loses some mass due to energy release during the process, often in the form of a supernova or gamma-ray bursts. The resulting black hole has a lower mass than the original star, but its mass is concentrated in a smaller volume, creating a steeper gravitational well. Additionally, as a black hole consumes matter, not all of that mass is added to its total due to energy emissions during the accretion process. Therefore, the net mass of a black hole formed from a star is less than the original mass of the star.

PREREQUISITES
  • Understanding of general relativity and gravitational collapse
  • Familiarity with the concepts of supernovae and gamma-ray bursts
  • Knowledge of mass-energy equivalence (E=mc²)
  • Basic principles of black hole formation and accretion processes
NEXT STEPS
  • Research the mechanisms of black hole formation without core collapse supernova events
  • Study the effects of energy release during stellar collapse and its impact on mass
  • Explore the dynamics of matter accretion in black holes and its energy emissions
  • Investigate the properties of gravitational wells and their implications for black hole physics
USEFUL FOR

Astronomers, astrophysicists, and students of physics interested in black hole formation, stellar evolution, and gravitational dynamics.

narrator
Messages
241
Reaction score
17
Basic question, I know... but..

When a star collapses and becomes a black hole, is it the same mass and does it have the same gravitational force of the original star? I heard something about it throwing off some of that mass in the process. And perhaps some aspect at the quantum level affects the gravity or mass.

As an extension of the question, once a BH consumes other masses, does the net mass equal the sum of the individual masses and is the gravitational force the sum of the gravitational forces of the original objects?
 
Astronomy news on Phys.org
I don't think there are any BHs that form by simple gravitational collapse (but I could be totally wrong about that) but if they DID then yes, they would have the same mass as a BH as they had as a star.

Any conglomeration of matter has a gravitational effect. Aside from places inside the radius of the conglomeration, the gravitational effect is indifferent to the radius of the conglomeration.
 
It is believed possible some stellar mass black holes can form without a core collapse supernova event.
 
Remember that E=mc^2

When a star collapses to form a black hole a great deal of energy is released, often in the form of a supernova and probably gamma ray bursts as well. Therefore the resulting black hole will have a lower mass than the original collapsar.

However, its mass will be concentrated in a tiny volume and so its gravitational well will have much steeper sides than that of the original star.

Similarly, when matter associated with spacetime that flows into a black hole gets strongly accelerated and ripped apart it also emits large amounts of energy and so not all of its mass/energy is added to that of the black hole.
 
Blibbler said:
Remember that E=mc^2

When a star collapses to form a black hole a great deal of energy is released, often in the form of a supernova and probably gamma ray bursts as well. Therefore the resulting black hole will have a lower mass than the original collapsar.

However, its mass will be concentrated in a tiny volume and so its gravitational well will have much steeper sides than that of the original star.

Similarly, when matter associated with spacetime that flows into a black hole gets strongly accelerated and ripped apart it also emits large amounts of energy and so not all of its mass/energy is added to that of the black hole.

Many thanks Blibbler, that's how I imagined it. Would you have any idea how much less net mass and how much less net gravitational force? Again, I imagine it would depend on the mass involved, but given how little mass is involved in releasing nuclear energy, I'm guessing the net result would be perhaps something like 99% of the original.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 87 ·
3
Replies
87
Views
10K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 48 ·
2
Replies
48
Views
6K