Statics Problem, Moment About an Axis

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SUMMARY

The discussion revolves around solving a statics problem involving the calculation of the moment about an axis using a determinant matrix. The user initially calculated the moment as -138.75 N*m but later corrected their approach after realizing they had not normalized the unit vector components correctly. The correct moment value is -111.0 N*m, achieved by properly dividing the unit vector components by their magnitude. The conversation highlights the importance of accurate vector normalization in statics problems.

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Homework Statement


Problem 3.60:
BgRMJLy.png



Homework Equations



M_{AD}= \begin{vmatrix}<br /> \lambda_x &amp; \lambda_y &amp; \lambda_z \\ <br /> x_{B/A} &amp; y_{B/A} &amp; z_{B/A} \\ <br /> F_x &amp; F_y &amp; F_z &amp; <br /> \end{vmatrix}<br />


The Attempt at a Solution



Looking at the figure, these are the unit vector components for line AD:

\lambda_x=1 \ m<br /> \\ \lambda_y= 0 \ m<br /> \\ \lambda_z = -0.75 \ m<br />

And these are the coordinates for point B where the force is applied:

x_{B/A}=0.5 \ m<br /> \\ y_{B/A}= 0 \ m<br /> \\ z_{B/A} = 0 \ m<br />

The force vector for the tension in BG:
\mathbf{T_{BG}}= 450*(\frac{-0.5\hat{i}+0.925\hat{j}-0.4\hat{k}}{1.125})= -200\hat{i}+370\hat{j}-160\hat{k} \ N

Plugging these values into the matrix above, I get -138.75 N*m, but the answer is supposed to be -111.0 N*m

Edit: Changed the mistake I made in the second row. Still getting the wrong answer.
 
Last edited:
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Shouldn't λx^2+λy^2+λz^2 = 1 if these are the components of a unit vector?
 
SteamKing said:
Shouldn't λx^2+λy^2+λz^2 = 1 if these are the components of a unit vector?

Yes, I actually just figured it out. I had messed up when I took the unit vector components and didn't divide by the magnitude.
Is there a way I can close this thread?
 
We don't delete threads that have responses. Glad that you figured it out. :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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