(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the displacement (mm) in the horizontal direction of point A due to the force, P. P=100kN w1=19mm w2=15mm

2. Relevant equations

[itex]\tau[/itex] = G * [itex]\gamma[/itex]

[itex]\tau[/itex] = Shear stress = P / A

[itex]\gamma[/itex] = Shear strain = (pi / 2) - [itex]\alpha[/itex]

3. The attempt at a solution

I haven't attempted to work out a solution here yet, but I do have a question regarding the separate G values that are given.

Can I just look at the top layer, the layer where P is acting, and use that G value to determine [itex]\delta[/itex]? Or do I need to do something with the other G value as well?

If I were to try something, I would find tau by doing 100[kN] / (100[mm] * 2[mm]). So tau would be equal to 1[kN]/2[mm^{2}] = 0.5[GPa]. Next I would find gamma by dividing tau by G (100[GPa]) giving me [itex]\gamma[/itex] = .005rad. I can use trig to define gamme as [itex]\gamma[/itex]=sin^{-1}([itex]\delta[/itex]/40). Setting this equal to .005 I would get [itex]\delta[/itex]= .20[mm].

Even if I do have to do something with both of the G values, I feel like my method is correct. Any help is appreciated, thanks in advance.

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# Statics Question (Using Modulus of Rigidity)

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