Statics - Support Reaction in Truss

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SUMMARY

The discussion focuses on determining support reactions in a truss system, specifically the reactions R_{fx}, R_{fy}, R_{kx}, and R_{ky}. The user initially derived four equations using equilibrium conditions but found the system unsolvable due to redundancy. It was clarified that the truss behaves as two rigid bodies hinged at joint e, allowing for the formulation of an independent torque balance equation. This insight resolved the user's confusion and led to a successful solution.

PREREQUISITES
  • Understanding of static equilibrium conditions in truss analysis
  • Familiarity with reaction forces in structural mechanics
  • Knowledge of rigid body dynamics and hinge behavior
  • Ability to formulate and solve torque balance equations
NEXT STEPS
  • Study the principles of static equilibrium in truss systems
  • Learn about the effects of different support types, such as roller supports
  • Explore the concept of hinge connections in structural analysis
  • Practice deriving and solving torque balance equations in truss problems
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Students and professionals in civil engineering, structural analysis, and mechanics who are involved in truss design and support reaction calculations.

Philippe
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Homework Statement


I'm having a hard time finding the support reactions R_{fx} ; R_{fy} ; R_{kx} ; R_{ky} in this truss.

2. The attempt at a solution

I got four equations using the equilibrium conditions (sum of forces along x and y ; sum of moments on F and on C) but the system doesn't seem to have a solution. Am i missing something?

<br /> (\Sigma x = 0) R_{fx} + R_{ky} = 0 \\<br /> (\Sigma y = 0) R_{fy} + R_{ky} = 530 \\<br /> (\Sigma M_{f} = 0) -8R_{kx} + 40R_{ky} = 11100 \\<br /> (\Sigma M_{c} = 0) -20R_{fx} + 20R_{fy} -12 R_{kx} - 20R_{ky} = -500<br />

Thanks!
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You have treated the whole girder system as a single rigid structure. That means there are only three independent equations available. Any further you write down, whether linear forces or moments, can be deduced from those three.

Is it a single rigid structure?
 
Yes exactly, I noticed that I can obtain the fourth equation from the first three so I need a fourth independent one.
But I'm under the impression that it is a single structure, I guess I'm wrong!
 
Philippe said:
Yes exactly, I noticed that I can obtain the fourth equation from the first three so I need a fourth independent one.
But I'm under the impression that it is a single structure, I guess I'm wrong!
Imagine replacing one of the end supports with a roller. Can you visualise what would happen in reality?
 
The horizontal component of the reaction force would be zero as it free to move in this direction on the end support, right?
 
Philippe said:
The horizontal component of the reaction force would be zero as it free to move in this direction on the end support, right?
Yes, but what would happen to the structure? Would it stay up?
 
No, it would collapse.
 
Philippe said:
No, it would collapse.
How, exactly?
 
The whole structure would "flatten" and be pushed to the right?
 
  • #10
Philippe said:
The whole structure would "flatten" and be pushed to the right?
To change shape, some joint must flex. Which one?
 
  • #11
Joint e ?
 
  • #12
Philippe said:
Joint e ?
Right. So the truss system is not in itself a rigid body. Rather, it is two rigid bodies hinged at e. This allows you to write a torque balance equation which is independent of the equations you already have.
Can you see how to do that?
 
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  • #13
Yes it worked!
Thanks a million!
 

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