Statistical mechanics. Partition function.

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SUMMARY

The discussion centers on the calculation of the partition function Z in statistical mechanics, specifically the transformation Z(αT, α^(-3/ν)V, N). The participants explore the relationship between the original partition function Z(T, V, N) and the transformed function, utilizing the equation Z(T, V, N) = (1/h^(3N)N!)(2πmkT)^(3N/2)∫...∫_V e^(-U/kT). The key challenge identified is integrating the term e^(-U/kαT) and ensuring that the integral over the transformed volume α^(-3/ν)V yields the correct scaling factor α^(-3N/ν).

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LagrangeEuler
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Homework Statement


If ##Z## is homogeneous function with property
##Z(\alpha T,\alpha^{-\frac{3}{\nu}}V,N)##
and you calculate Z(T,V,N). Could you calculate directly ##Z(\alpha T,\alpha^{-\frac{3}{\nu}}V,N)##.


Homework Equations


##Z(T,V,N)=\frac{1}{h^{3N}N!}(2\pi m k T)^{\frac{3N}{2}}\int...\int_{V} e^{-\frac{U}{kT}}##



The Attempt at a Solution


When I have for exaple
##Z(\alpha T,\alpha^{-\frac{3}{\nu}}V,N)=\frac{1}{h^{3N}N!}(2\pi m k \alpha T)^{\frac{3N}{2}}\int...\int_{\alpha^{-\frac{3}{\nu}}V} e^{-\frac{U}{k\alpha T}}##
I'm not sure how to integrate this ##e^{-\frac{U}{k\alpha T}}## in exponent.
[
 
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From this if I understand well
##\int...\int_{\alpha^{-\frac{3}{\nu}V}}e^{-\frac{U}{k\alpha T}}##
need to be equal
##\int...\int_{\alpha^{-\frac{3}{\nu}V}}e^{-\frac{U}{k\alpha T}}=\alpha^{-\frac{3N}{\nu}}...##
 

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