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[Statistical Physics] No. of dice rolls so prob of getting a 6 is >90%

  1. Apr 11, 2014 #1
    This question is really wearing me out, any ideas?

    1. The problem statement, all variables and given/known data

    How many times must I throw a fair dice in order to make the probability of getting at least one ‘6’ greater than 90%?
    With this many throws, what is the probability of getting three ‘6’s?

    It's the first part I'm struggling with.

    2. Relevant equations

    The relevant question is the one on the top of the pic attached.

    P = probability of outcome interested in
    N = number of throws

    3. The attempt at a solution


    I'm using P(1) as the probability of getting 1 six, so n=1.
    For the second part of the equation I would use P(3).

    Attached Files:

  2. jcsd
  3. Apr 11, 2014 #2
    You are trying to calculate the probability of getting one 6. The question is what's the probability of getting AT LEAST one six. that includes two 6s, three 6s, etc. Try calculating the probability of getting NO 6s. That should be 10% since 90% of the time you're getting at least one 6.
  4. Apr 11, 2014 #3


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    You want to consider the probability of getting at least one six. That would include the probability of getting two sixes, or three sixes, .... or N sixes.

    How does the probability of getting at least one six in N throws relate to the probability of getting no sixes in N throws?

    edit: I've added nothing to what dauto already said.
  5. Apr 11, 2014 #4
    "At least"... such a rookie mistake missing something like that. It's unreal how much time I've just wasted.

    Thanks, I've got it now.
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