Statistical physics Q: macrostates

Click For Summary
SUMMARY

The discussion centers on determining the possible macrostates of a system with 5 Bosonic particles distributed across 2 degenerate energy levels, E1 and E2, with statistical weights g1 = 3 and g2 = 2. The correct conclusion is that there are 3 distinct macrostates characterized by total energy configurations: E = 5 E1, E = 4 E1 + E2, and E = 3 E1 + 2 E2. The initial confusion regarding the count of 13 macrostates arises from a misunderstanding of how to combine the energy levels and their respective statistical weights.

PREREQUISITES
  • Understanding of Bosonic particles and their statistical behavior
  • Familiarity with the concept of macrostates and microstates in statistical mechanics
  • Knowledge of energy levels and statistical weights in quantum systems
  • Basic principles of combinatorial counting in physics
NEXT STEPS
  • Study the principles of Bosonic statistics and their implications in quantum mechanics
  • Learn about the relationship between macrostates and microstates in statistical physics
  • Explore combinatorial methods for counting states in quantum systems
  • Investigate the role of degeneracy in energy levels and its effect on statistical distributions
USEFUL FOR

Students and researchers in physics, particularly those focusing on statistical mechanics, quantum mechanics, and thermodynamics, will benefit from this discussion.

Irishdoug
Messages
102
Reaction score
16

Homework Statement



There are 5 Bosonic particles N = 5 populating 2 degenerate energy levels E1 and E2 such that:

E1 < E2, N2 ≤ N1

and the respective statistical weights are

g1 = 3 and g2 = 2.
.

What are the possible macrostates of this system?

The Attempt at a Solution

I'm not sure if the answer is: for E1 either 5 or 4 or 3 macrostates (as N1>N2)

and for E2 either 2 or 1 macrostates.

or

13 macrostates:

E1 , g = 3

E1 N1 = 5 --> (5,0,0) (410) (320) (311)
E1 N1 = 4 --> (400) (310) (220)
E1 N1 = 3 --> (300) (210) (111)

E2 , g = 2

E2 N2 = 2 --> (2,0) (1,1)
E2 N2 = 1 --> (1,0)

so 13 macrostates overall.

Any idea which is correct or are they both wrong!
 
Last edited:
Physics news on Phys.org
In the attempt, I don't understand why you are considering separately E1 and E2.

A macrostate is characterized by its total energy. Therefore, I count 3 macrostates:
E = 5 E1
E = 4 E1 + E2
E = 3 E1 + 2 E2
 
  • Like
Likes   Reactions: Greg Bernhardt

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
18K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
5K