Heat capacity (statistical physics)

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Homework Help Overview

The discussion revolves around a statistical physics problem involving a system with three energy levels and their respective degeneracies. The task is to find the heat capacity of the system, which requires an understanding of thermodynamic concepts and the partition function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the importance of the partition function as a starting point for calculating thermodynamic quantities. There are attempts to derive expressions for internal energy and heat capacity based on the given energy levels and degeneracies.

Discussion Status

Some participants have provided insights into the calculation of the partition function and internal energy, suggesting a direction for further exploration. However, the discussion does not indicate a consensus on the final approach to finding the heat capacity.

Contextual Notes

The original poster expresses uncertainty about thermodynamic concepts, indicating a potential gap in foundational knowledge that may affect their ability to engage with the problem fully.

broegger
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Hi. I've just started a course on statistical physics and the first assignment is this:

A system possesses 3 energy levels, [tex]E_1 = \epsilon,[/tex] [tex]E_2 = 2\epsilon[/tex] and [tex]E_3 = 3\epsilon[/tex]. The degeneracy of the levels are g(E1) = g(E3) = 1, g(E2) = 2. Find the heat capacity of the system.

I've forgotten all this thermodynamics stuff, so I would appreciate some hints :-)
 
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Anyone? Please :rolleyes:
 
If you are given a description of a system, what quantity do you first compute, from which you can determine other thermodynamic quantities ?
 
Yes, yes, the partition function, I know :-)
 
sum over states to get Q

Q= exp{-B.E) + 2exp{-B.2E} + exp{-B.3E}

B=kT Q=partition E=energy (two in front of second term beacuse of degenercy)


U= - Diff (lnQ) w.r.t (B)

U= internal energy prof can be found ( http://www.chem.arizona.edu/~salzmanr/480b/statt01/statt01.html)... if you are interested

gives U= E.exp(-B.E) + 4E.exp(-B.2E) + 3E.exp(-B.3E)

makes sense highest energy has least probability of being populated but contributes three times as much to internal energy when it is. same would apply to the middle state but there is two of them so it is four instead of two.
 

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