1. The problem statement, all variables and given/known data A certain die is weighted such that probabilities of showing a 1, 2, 3, 4, 5, and 6 are (6/34), (8/34), (5/34), (3/34), (8/34), and (4/34) A) If two such dice are thrown, and you are told that the sum of the two is 10 or larger. What is the probability that the result was a pair of 5's? B) How many times would you have to throw this die to have the probability of throwing a 2 exceed 40 percent? 2. Relevant equations 3. The attempt at a solution A) For this the possible outcomes for a sum of 10 or greater are: 4-6 5-5 5-6 6-4 6-5 6-6 Getting rid of duplicates, since order doesn't matter there is a 1/4 chance it's double fives. I multiplied this by (8/34)(8/34) and got a probability of .01384 B) For this I used the equation Probability = Successful outcomes/Total number of outcomes so .4 = (8/34)/n solving for n I get .588, which doesn't make sense. I'm just learning statistics, so if anything I tried to do offends you mathematically, I'm very sorry!