Step-by-Step Guide to Factoring Polynomials: Solving a Tricky Problem

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The polynomial 16a^2 - 24ab + 9b^2 - 25c^2 can be factored by first recognizing the first three terms as a perfect square, resulting in (4a - 3b)^2. This expression then leads to the difference of squares format, allowing for further factoring. The final factored form is (4a - 3b + 5c)(4a - 3b - 5c). It's recommended to multiply the factors back to verify the solution. This method effectively simplifies the polynomial while ensuring accuracy in the results.
Hollysmoke
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I am stuck on this one polynomail factoring problem and I was wondering if someone could help me with it:

16a^2 - 24ab + 9b^2 - 25c^2

I tried factoring the first 3 terms as a trinomial but I'm not sure if that's what I'm supposed to do. What I wrote down so far is:

(4a -5c)(4a +5c)
 
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Note: There should be a space between the 5c and 4a
 
Hint: Express the first three terms as a perfect square then factor the difference between squares. :)
 
Hollysmoke said:
I am stuck on this one polynomail factoring problem and I was wondering if someone could help me with it:

16a^2 - 24ab + 9b^2 - 25c^2

I tried factoring the first 3 terms as a trinomial but I'm not sure if that's what I'm supposed to do. What I wrote down so far is:

(4a -5c)(4a +5c)

(16a^2-24ab+9b^2)-25c^2
(4a-3b)^2-25c^2

Now note that this is in the form of the difference of two squares, i.e.
x^2-y^2 = (x+y)(x-y) where x = 4a-3b and y = 5c. So finally:
(16a^2-24ab+9b^2)-25c^2 = (4a-3b+5c)(4a-3b-5c).

(And, of course, always multiply it back out to check the answer.)

-Dan
 
and of course, after you find X, put it into the original problem to make sure your value works.
 
I think you should leave something for the OP to do! :)
 

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