- #1

ProjectTruth

- 17

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Member warned about posting homework without the template

Hey Guys,

So I'm currently factoring polynomials.

As you all know,when trying to factor a polynomial with 4 terms,the answer can be the difference of a trinomial and monomial squares.

So I had the problem 4a^2-4ab+b^2-c^2

I thought(book doesn't explain it well) that your first step was to group like terms to create your trinomial which we then end up with:

(4a^2-4ab+b^2)-c^2

From there we solve and get:

(2a-b)^2-c^2

Thus being solved:

=(2a-b-c)(2a-b+c)

Which is the correct answer.

But then they had this problem:

a^2+b^2-c^2-2ab

My logic behind grouping like terms then falls short in this one,in which I now assume we just randomly select 3 terms to isolate. This is where things start getting sticky...

The correct answer is (a-b+c)(a-b-c)

But I can't seem to find my order of operations...

I find that I group (a^2-b^2+c^2)-2ab

But that's as far as I get...

Any insight?

Thanks in advance.

So I'm currently factoring polynomials.

As you all know,when trying to factor a polynomial with 4 terms,the answer can be the difference of a trinomial and monomial squares.

So I had the problem 4a^2-4ab+b^2-c^2

I thought(book doesn't explain it well) that your first step was to group like terms to create your trinomial which we then end up with:

(4a^2-4ab+b^2)-c^2

From there we solve and get:

(2a-b)^2-c^2

Thus being solved:

=(2a-b-c)(2a-b+c)

Which is the correct answer.

But then they had this problem:

a^2+b^2-c^2-2ab

My logic behind grouping like terms then falls short in this one,in which I now assume we just randomly select 3 terms to isolate. This is where things start getting sticky...

The correct answer is (a-b+c)(a-b-c)

But I can't seem to find my order of operations...

I find that I group (a^2-b^2+c^2)-2ab

But that's as far as I get...

Any insight?

Thanks in advance.