Step-by-Step Guide to Factoring Polynomials: Solving a Tricky Problem

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Homework Help Overview

The discussion revolves around a polynomial factoring problem involving the expression 16a^2 - 24ab + 9b^2 - 25c^2. Participants are exploring methods to factor this polynomial and are considering various approaches to achieve that.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to factor the first three terms as a trinomial and expresses uncertainty about their approach. Some participants suggest expressing the first three terms as a perfect square and then factoring the difference of squares. Others note the importance of checking the work by multiplying back out.

Discussion Status

Participants are actively discussing different methods for factoring the polynomial. While some guidance has been offered regarding the perfect square and difference of squares, there is no explicit consensus on the final approach, and the original poster is encouraged to engage further with the problem.

Contextual Notes

There is a note about ensuring proper spacing in the expressions, and one participant emphasizes the importance of leaving some work for the original poster to complete.

Hollysmoke
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I am stuck on this one polynomail factoring problem and I was wondering if someone could help me with it:

16a^2 - 24ab + 9b^2 - 25c^2

I tried factoring the first 3 terms as a trinomial but I'm not sure if that's what I'm supposed to do. What I wrote down so far is:

(4a -5c)(4a +5c)
 
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Note: There should be a space between the 5c and 4a
 
Hint: Express the first three terms as a perfect square then factor the difference between squares. :)
 
Hollysmoke said:
I am stuck on this one polynomail factoring problem and I was wondering if someone could help me with it:

16a^2 - 24ab + 9b^2 - 25c^2

I tried factoring the first 3 terms as a trinomial but I'm not sure if that's what I'm supposed to do. What I wrote down so far is:

(4a -5c)(4a +5c)

[tex](16a^2-24ab+9b^2)-25c^2[/tex]
[tex](4a-3b)^2-25c^2[/tex]

Now note that this is in the form of the difference of two squares, i.e.
[tex]x^2-y^2 = (x+y)(x-y)[/tex] where x = 4a-3b and y = 5c. So finally:
[tex](16a^2-24ab+9b^2)-25c^2 = (4a-3b+5c)(4a-3b-5c)[/tex].

(And, of course, always multiply it back out to check the answer.)

-Dan
 
and of course, after you find X, put it into the original problem to make sure your value works.
 
I think you should leave something for the OP to do! :)
 

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