What mass of iron(III) chlorate is needed to precipitate all the chromate ions from 234 mL of a 0.100 M lithium chromate solution.
The Attempt at a Solution
we just started precipitates and my teacher didnt explain the procedure very well so if u can get me on the correct track for solving it, it would be appreciated.
i made a balanced equation for the reaction
2Fe(ClO3)3 + 3Li2CrO4-->6LiClO3 + Fe2(CrO4)3
then the net ionic equation 2Fe3+ + 3CrO42--->Fe2(CrO4)3
then i used molarity equations to find 0.1M=xmol/.234L --> 0.0234 mol Li2CrO4
but i am not sure where to go from here, any help?