Stopping distance given frictional force

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Homework Help Overview

The discussion revolves around calculating the stopping distance of a vehicle on a level, dry concrete road, given the frictional force as a percentage of the vehicle's weight. The vehicle's speed is provided, and participants are exploring the implications of the frictional coefficient and the relationship between friction and weight.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion regarding the frictional coefficient and its relationship to the weight of the vehicle. There are attempts to clarify the formula for frictional force and its components, with questions about how to derive necessary values from the information provided.

Discussion Status

The discussion is ongoing, with participants seeking clarification on key concepts such as the frictional coefficient and the normal force. Some guidance has been offered regarding the use of kinematic equations, but there is no consensus on how to proceed with the calculations.

Contextual Notes

Participants note a lack of specific information regarding the weight of the vehicle, which is critical for solving the problem. There is also an expressed urgency to complete the assignment, contributing to the pressure felt by some participants.

Chica1975
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Homework Statement


In an emergency stop on a level, dry concrete road, the magnitude of the friction force when sliding is approx 80% of the weight of the vehicle what is the stopping distance required for a vehicle traveling at 88km/h (24.444m/s). assume that all the wheels lock when the brakes are applied.

Homework Equations


to be honest i freaked out when I saw this question - i looked at my textbook but it really is useless.
is the frictional coefficient .20?


The Attempt at a Solution



I have no idea what to do
apparently the answer is 38m
 
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Chica1975 said:

Homework Statement


In an emergency stop on a level, dry concrete road, the magnitude of the friction force when sliding is approx 80% of the weight of the vehicle what is the stopping distance required for a vehicle traveling at 88km/h (24.444m/s). assume that all the wheels lock when the brakes are applied.

Homework Equations


to be honest i freaked out when I saw this question - i looked at my textbook but it really is useless.
is the frictional coefficient .20?


The Attempt at a Solution



I have no idea what to do
apparently the answer is 38m

Not 0.2. Remember that the frictional force is F = mu * N, where in this case, N is the weight of the car. So what is mu?

Anyway, if the frictional force is constant (which it is in this problem), you use the kinematic equations of motion for constant accerleration (just like you use for gravity-related problems). What is the equation that relates the velocity to the applied acceleration (or deceleration in this case)?
 
I have no idea what mu is and N I don't have just that vehicle is traveling at 88km/h. I am ok with the kinematic equations when I have the numbers to plug in. I have no idea how to get the N for the weight of the vehicle just by being given that the frictional force is 80% the weight of the vehicle.
 
can someone please tell me how to do this? I have no idea how to workout the weight of the car. I need to hand this in. Without it being explained I really don't know what i am doing in the least.
 

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