1. The problem statement, all variables and given/known data Two capacitors of 2.0F and 5.0F are connected in series; the combination is connected to a 1.5 volt battery. What is the charge stored on each capacitor? What is the potential difference across each capacitor? 2. Relevant equations C = Q / (Delta)V 3. The attempt at a solution Since the capacitors are in series, we can find the equivalent capacitance by solving: 1/Ceq = 1/2.0F + 1/5.0F Ceq = 1.429F I then used this value to find the charge on each plate of each capacitor C = Q/V CV = Q 1.429F * 1.5V = 2.143 So now I now the amount of charge on each plate. Using this value in conjunction with a specific capacitance, I can find the potential difference across any given capacitor whose capacitance I know. so, V = Q/C 2.143/2 = 1.072V 2.143/5 = .429V Thank you for the help.