Estimating Bullet Terminal Velocity from Fracture Energy of Tempered Glass

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Homework Help Overview

This discussion revolves around the relationship between stress, strain, and energy in the context of materials, specifically focusing on the fracture energy of tempered glass and its implications for estimating bullet terminal velocity. The original poster attempts to connect the concepts of stress and energy stored in materials, while also exploring the properties of tempered glass relevant to its fracture behavior.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the units of stress and energy, questioning where discrepancies arise in their calculations. There is an exploration of the relationship between failure stress and fracture energy, with some participants seeking clarification on definitions and the implications for estimating terminal velocity based on energy requirements for fracture.

Discussion Status

The discussion is ongoing, with participants providing hints and definitions to clarify concepts. Some guidance has been offered regarding the definitions of energy and stress, while multiple interpretations of fracture energy and its relevance to the problem are being explored.

Contextual Notes

Participants are navigating the complexities of material properties, specifically the distinction between fracture energy and failure stress, and how these relate to the energy required for penetration of materials. There is a noted lack of consensus on the definitions and relationships involved.

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1. The question
This question is about the design of a car seat belt. The seat belt restraints a passenger when the car is involved in an accident.

Use definitions of stress and strain to show that stress x strain has the same units as energy stored per unit volume of seat belt.

Homework Equations


Deriving question hence no specific equation required.

The Attempt at a Solution


stress x strain = force/area x extension\length = Nm/m^3 = N/m^2 = Nm^(-2)
energy stored per unit volume of seat belt = J/m^34. The problem occurring
I am not getting the same unit so it's contradicting the question. Can I have help as to where I have gone wrong. :confused: Thanks in advance.
 
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HINT: What is the definition of the Joule? (In terms of Newtons)
 
Joules = Newton Meter

energy stored per unit volume of seat belt = J/m^3 = Nm/m^3 = N/m^2 = Nm^(-2).

:smile: Thanks.
 
Air said:
Joules = Newton Meter

energy stored per unit volume of seat belt = J/m^3 = Nm/m^3 = N/m^2 = Nm^(-2).

:smile: Thanks.
A pleasure :smile:
 
hi, I have a question about this relation btw Stress/Energy.
if I know the failure stress/fracture of tempered glass, (~17000 psi = 117 MPa),
how do I relate that to fracture energy of that glass? or are they completely different things?

Energy = J = Nm
Stress = N/m^2
need a volume multiplyer to get J ?

basically, I need fracture energy of tempered glass, and so far, I was only able to find
failure stress of glass.

thank you.
 
Hi wooz, welcome to PF. Can you define what you mean by fracture energy here? There are several different energies associated with brittle fracture. The one often described as "fracture energy" has units J m-2 and incorporates crack length. On the other hand, the fracture toughness of tempered glass is a material constant that doesn't depend on crack length, but does depend on loading geometry. It would help if you told us a little more about what kind of information you need.
 
thanks Mapes. sorry about the poor wording.
basically, I need to estimate the bullet terminal velocity from the fracture energy of tempered glass when it breaks. E = 0.5mv^2, I know the mass of bullet. I can estimate the velocity when I know the energy right?

for example, to penetrate human skin, it requires 20 J/cm^2.
I know the mass, area of bullet, then I can estimate the terminal velocity.

I guess I should say energy require to fracture/penetrate tempered glass.
not sure if failure stress of tempered glass is actually related to the fracture energy.

thanks.
 

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