Structure of elements of the unitary group

  • #1
489
0
Hey guys,

I'm having a massive brain freeze here trying to show that for any element g in the unitary group you can always represent it as s*some diagonal matrix*s^-1. The only requirement for an element to be unitary is that its hermitian conjugate is its inverse correct? Any hints/help would be appreciated!

Cheers
-G
 
Last edited:

Answers and Replies

  • #3
Ah i think i see what youre saying, its kind of a basis transformation thing? I sort of understand that (not in a way to provide a proper proof though) but is there a way to arrive at that relation just from the strict definition of a unitary matrix?

Cheers
-G
 
  • #4
It inevitably follows from a theorem in Linear algebra that states every unitary matrix is diagonalizable. You can probably find it in some L(Alg) textbook or alternatively you can simply google that statement.
 

Suggested for: Structure of elements of the unitary group

Replies
2
Views
734
Replies
13
Views
1K
Replies
3
Views
509
Replies
1
Views
736
Replies
7
Views
438
Replies
3
Views
693
Back
Top