Struggling with Practice Test Questions on Electromagnetism?

  • Thread starter Thread starter AznBoi
  • Start date Start date
  • Tags Tags
    Test
Click For Summary

Homework Help Overview

The discussion revolves around practice test questions related to electromagnetism, including concepts such as electric potential, forces on charges, and Lenz's law. Participants are attempting to clarify their understanding of these topics through various problem statements.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are sharing their attempts at solving specific problems, questioning their approaches, and seeking clarification on concepts such as electric potential and induced currents. Some are exploring the relationship between electric force and work, while others are discussing the implications of Lenz's law.

Discussion Status

Some participants are offering hints and guidance without providing direct answers. There is an ongoing exploration of different interpretations of the problems, particularly regarding the calculations of potential and the application of physical laws. The discussion is active, with participants seeking to refine their understanding and clarify their reasoning.

Contextual Notes

Participants are working with incomplete information, such as missing diagrams and specific values, which may affect their ability to solve the problems accurately. There is also a mention of imposed homework rules that restrict the sharing of direct answers.

AznBoi
Messages
470
Reaction score
0
http://img148.imageshack.us/img148/7599/981718254748dd2.png
My work, my answers are wrong obviously.

18. [tex]U_{E}=\frac{kq1q2}{d}[/tex] -- I substituted the electric force with the work equation to get this.

25. Q=mL, Q=mcT . I combined these to get mL=mcT, stuck from there.

47. F=q(v x B), v=F/qB, F=mv^2/r
I combined these equations to get: mv/r=qB and solved for v and I then I just guessed.

48. Why is the answer D?? I know that it has something to do with lenz's law but I only know how to apply that law for magnets moving with either North or South pole. (If a north pole of a magnet moves towards the wire the induced current is counter clockwise right? If the south pole moves into the wire it is clock wise?)-- Is this right?

Thanks for your help guys! =]
 
Last edited by a moderator:
Physics news on Phys.org
Sorry we are not giving answers as such. You may get hints for your doubts and confusions only. Show your approach in case not getting the correct answers.
 
Oh, I just posted the picture first to see if it worked lol. Anyways, my attempts are on the board! Do you want me to post the answers too? I have the answer key btw, just not the solutions.
 
Is the diagram is given? Should be, otherwise what is Q? what about the position of the point P?
 
mukundpa said:
Is the diagram is given? Should be, otherwise what is Q? what about the position of the point P?
Yeah, I realized that lol. I forgot to include the picture because I got 17 right. So for 17, all I did was add the two electric field vectors (one to the left and one down) to get the resultant vector which is (c) right? Thanks.
 
Now it is clear. There are two charges Q both at a distance d from the third corner of the square.

Find potential V at that point due to both Q charges (Potential is a scalar quantity) then multiply q and V.
 
For the next heat is required to first increase the temperature of ice up to the melting point then latent heat to melt and then to increase temperature of water.
 
For the next you got the relation for v. Put the value of e/m for proton and probable values of B and r and will get the order of the velocity.
 
mukundpa said:
Now it is clear. There are two charges Q both at a distance d from the third corner of the square.

Find potential V at that point due to both Q charges (Potential is a scalar quantity) then multiply q and V.

So how do you find the potential v at the point? I know that [tex]V=\frac{U_{e}}{q} =Ed[/tex]
I don't get what you mean by then multiply q and v.
 
  • #10
The potential at that point will be KQ/d due to each charge Q so what is the total potential? and what is the potential energy?
 
  • #11
mukundpa said:
The potential at that point will be KQ/d due to each charge Q so what is the total potential? and what is the potential energy?

OKay, so [tex]\frac{kQ}{d}+\frac{kQ}{d}=2\frac{kQ}{d} *q= 2k\frac{qQ}{d}[/tex]? So how do you know that you need to add the potential differences rather than just the potential energies? You can do it either way right? So do you just add them because they are a scalar? Is there any time where you need to subtract them? (mabye when the charges are opposite?) So if the quantities are scalar you just add them and if they are vectors you need to use pythagorean or trig right?
 
  • #12
Going in the right direction.
 

Similar threads

  • · Replies 40 ·
2
Replies
40
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
6
Views
2K
Replies
12
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K