Stuck with calculating torque needed for Robot servo motion

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Discussion Overview

The discussion revolves around calculating the torque required for a motor shaft to spin a mass attached to a rod, considering both the torque needed for acceleration and the torque due to gravity. The scope includes theoretical calculations and practical applications in robotics.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests using the equation Torque = inertia * angular acceleration to calculate the maximum torque required.
  • Another participant proposes that an additional component of torque is necessary to account for the gravitational weight of the mass, particularly when the axis of rotation is horizontal.
  • A participant confirms their rotational axis is horizontal and questions whether the torque required to overcome gravity should be added to the torque required for circular motion acceleration, noting that speed may influence the torque required.
  • Another reply indicates that for the worst-case scenario, the torques can be added when the center of mass is at a 90-degree angle, but cautions that this may overestimate the torque needed when the center of mass is on the opposite side.
  • It is mentioned that speed does not affect the maximum torque caused by gravity or rotational inertia.

Areas of Agreement / Disagreement

Participants express differing views on whether the torque due to gravity should be added to the torque for acceleration, and there is no consensus on how speed influences the required torque.

Contextual Notes

Participants have not fully resolved the assumptions regarding the effects of speed on torque calculations or the conditions under which the torque components should be combined.

Robo3
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Hi there,

I was wondering if you could help me with a quick problem. I should probably know this but for some reason I am getting confused between different points of view:

If I wanted to calculate the maximum torque required by a motor shaft to spin a mass at the end of a rod connected to the motor shaft I would use the eqn:

Torque = inertia*angular acceleration

However would there not also be an extra component of torque due to the gravitational weight of the mass?

Thanks in advance
 
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If the axis of rotation is horizontal -

Find distance (r) of the center of mass from the axis of rotation.
The torque required to overcome gravity in the worst position is T = mass * g * r

If the axis isn't horizontal, replace g with an in-the-plane-of-rotation component of mass*g
 
Thankyou, my rotational axis is horizontal.

Do I need to add the torque required to overcome gravity to the torque required to accelerate the mass in a circular motion though? Surely the speed that the mass rotates at affects the torque required by the motor shaft?

Thanks again
 
Robo3 said:
Do I need to add the torque required to overcome gravity to the torque required to accelerate the mass in a circular motion though? Surely the speed that the mass rotates at affects the torque required by the motor shaft?

Just add them for the worst cast (accelerating while lifting with the CoM 90degrees). But that'll tell you more torque than what's needed when the CoM goes over the other side and is being pushed down.

Speed doesn't affect the maximum torque caused by gravity or rotational inertia.
 

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