Studying for math test - A few things I dont understand

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SUMMARY

The discussion focuses on solving a cubic polynomial equation, specifically x³ + 2x² + ax + b, given that (x + 1) and (x - 2) are factors. The user attempts to find the coefficients a and b by substituting the roots into the equation, resulting in incorrect values. The correct approach involves setting up simultaneous equations based on the roots and using polynomial division to find the remaining factor. The final factor can be determined either through polynomial division or by recognizing the relationship between the roots.

PREREQUISITES
  • Understanding of polynomial functions and their factors
  • Knowledge of solving simultaneous equations
  • Familiarity with polynomial division techniques
  • Concept of roots and their properties in cubic equations
NEXT STEPS
  • Study polynomial division methods for finding factors of cubic equations
  • Learn about the Rational Root Theorem for identifying potential roots
  • Explore the concept of conjugate pairs in polynomial roots
  • Practice solving simultaneous equations with multiple variables
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Students preparing for math tests, particularly in algebra and polynomial functions, as well as educators seeking to clarify polynomial factorization techniques.

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I have a math test coming up and I have last years test in front of me for a study guide. I can do most of the questions on this test and I know the theory behind everything on it but here's a couple of questions that I can't seem to get right.

Q1) If (x + 1) and (x - 2) are factors of x3 + 2x2 + ax + b find the values of a,b E(that greek symbol that looks like a rounded E) R, and find remaining factor.
I assumed that to find a and b I would have to plug each root -1 and 2 into the equation so I have 2 simultaneous equations but it didn't work out for some reason.

Heres what I did
(-1)3 + 2(-1)2 + a(-1) + b = 0 =>a - b = 1
did the same with the other root and got
2a + b = 16

by elimination I got A=17/3 and B=5 but these don't seem to plug into the equation. Am I going about this question the right way?

Also it asks me to find the last factor. I know I can do that by dividing the factors I have into the equation but is that the quickest method to obtaining the final factor when you already have 2?
 
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You can do it 2 ways,

1) you know that (x+1) and (x-2) are factors of that cubic, therefore you know the last root is real too (conjugate pairs and such) so it will be of the form (x - z)

So x^3 + 2x^2 + ax + b = (x+1)(x-2)(x-z), figure it out :)

2) since (x+1) and (x-2) are roots of that equation, then if we define

f(x) = x^3 + 2x^2 + ax + b, then f(-1) = f(2) = 0

Therefore -1 + 2 - a + b = 0 i.e. 1 - a + b = 0 which gives us a - b = 1 as you said

and

8 + 8 + 2a + b = 0 i.e. 16 + 2a + b = 0 which is the same as 2a + b = -16 which is not what you have. Maybe you want to try again?
 

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