Subgroup of external direct product

Click For Summary
SUMMARY

The discussion focuses on subgroup identification within the direct sum of cyclic groups, specifically Z40⊕Z30 and Z12⊕Z18. The user successfully identifies two subgroups of order 12 in Z40⊕Z30, namely <(10,10)> and <(10,5)>. Additionally, they find a subgroup <(3,2)> in Z12⊕Z18, which has the same order as Z9⊕Z4 but requires further verification for isomorphism. The need for a concrete isomorphism between <(3,2)> and Z9⊕Z4 is emphasized as a critical next step.

PREREQUISITES
  • Understanding of cyclic groups and their properties
  • Familiarity with direct sums of groups
  • Knowledge of subgroup orders and isomorphism criteria
  • Basic experience with group theory terminology
NEXT STEPS
  • Study the structure of direct sums in group theory
  • Learn how to determine isomorphisms between groups
  • Explore the concept of subgroup generation in cyclic groups
  • Investigate the application of the Fundamental Theorem of Finitely Generated Abelian Groups
USEFUL FOR

This discussion is beneficial for students and professionals in mathematics, particularly those specializing in abstract algebra, group theory, and anyone working on problems involving cyclic groups and their substructures.

xmcestmoi
Messages
11
Reaction score
0
I am trying to do the followin 2 problems but not sure if I am doing them correct.
Anyone please have a look...


1. In Z40⊕Z30, find two subgroups of order 12.

since 12 is the least common multiple of 4 and 3, and 12 is also least common multiple of 4 and 6.
take 10 in Z40, and 10 generates a subgroup of Z40 of order 4, that is <10>={0,10,20,30}

take 10 in Z30, 10 generates a subgroup of Z30 of order 3, that is <10>={0,10,20}

take 5 in Z30, 5 generates a subgroup of Z30 of order 6, that is <5>={0,5,10,15,20,25}

Answer: two subgroups of Z40+Z30 with order 12 are <(10,10)> and <(10, 5)>


2. Find a subgroup of Z12⊕Z18 isomorphic to Z9⊕Z4.

order of Z9⊕Z4 is 36, which is the least common multiple of 9 and 4.

Now find a subgroup of Z12⊕Z18 with order 36.
take 3 in Z12, 3 generates a subgroup of Z12 with order 4, that is <3>={0,3,6,9}

take 2 in Z18, then 2 generates a subgroup of Z18 with order 9, that is <2>={0,2,4,6,8,10,12,14,16}.

Answer: a subgroup isomorphic to Z9+Z4 is <(3,2)> in Z12⊕Z18.
 
Physics news on Phys.org
(1) looks good.

In (2), your answer is correct, but all you've shown is a subgroup with the same order as Z9⊕Z4. Being isomorphic is much stronger than having the same order, though, so you're not finished on (2) yet. Try to exhibit an isomorphism, e.g.
 
Thank you :) I will try to come up with an isomorphism from <(3,2)> to Z9⊕Z4
 
Last edited:

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
12K
  • · Replies 5 ·
Replies
5
Views
3K