Substance is in equilibrium between its vapour and liquid

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SUMMARY

The discussion centers on the concept of equilibrium between a substance's vapor and liquid phases, specifically addressing whether dissolved gas molecules are included in this equilibrium. It is established that once a water molecule is in the liquid phase, it cannot be distinguished from other molecules, thus all molecules contribute to the equilibrium. Each substance in a solution maintains its own gas/liquid equilibrium, allowing for the possibility of multiple equilibria within the same solution.

PREREQUISITES
  • Understanding of chemical equilibrium principles
  • Familiarity with phase changes in chemistry
  • Knowledge of gas solubility in liquids
  • Basic concepts of molecular interactions in solutions
NEXT STEPS
  • Research the principles of chemical equilibrium in detail
  • Study the phase transition processes, particularly evaporation and condensation
  • Explore the concept of solubility and its effect on equilibrium
  • Investigate the behavior of solutions with multiple solutes and their equilibria
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Chemistry students, educators, and professionals interested in understanding phase equilibria, gas solubility, and molecular interactions in solutions.

MathewsMD
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In Chemistry, if a substance is in equilibrium between its vapour and liquid, does it account for the dissolved gas molecules?

I have always heard that the rate of evaporate = rate of condensation in a case like this, but does the rate of evaporation include the dissolved gases escaping and other gas molecules dissolving? Since can this be technically considered a change of state since it is becoming aqueous (if water solvent) but what is it called if the solvent is the same substance? In either case, water or the same substance acting as the solvent, is this accounted for in the equilibrium equation or is this completely different?
 
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MathewsMD said:
In Chemistry, if a substance is in equilibrium between its vapour and liquid, does it account for the dissolved gas molecules?

I have always heard that the rate of evaporate = rate of condensation in a case like this, but does the rate of evaporation include the dissolved gases escaping and other gas molecules dissolving? Since can this be technically considered a change of state since it is becoming aqueous (if water solvent) but what is it called if the solvent is the same substance? In either case, water or the same substance acting as the solvent, is this accounted for in the equilibrium equation or is this completely different?
The short answer is that it's already accounted for. It is not possible to distinguish "dissolved" water molecules in the liquid from the rest of the molecules in the liquid. Once a water molecule enters the liquid, it is just the same as any other water molecule in the liquid (since it undergoes rapid collisions and exchanges energy rapidly).
 
Each substance present in the solution has its own separate gas/liquid equilibrium, so you can have solution that is in equilibrium in regard to one substance and not in equilibrium with regard to another. But it can also be in equilibrium in regard to all substances.
 

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