Substituting p=x^2 for Solving Polynomial Equation by Hand

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is there a way to solve this by hand
(1/2)x^4-x^2-1=0
 
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(1/2)x^4-x^2-1=(1/2)p^2-p-1=0

quadratic in p

[1+||- (1+2)^(1/2) ] = 1+||-3^(1/2) = p = x^2

x=+||-[1+||-3^(1/2) ]^(1/2) =+||-[1+3^(1/2) ]^(1/2)