Substituting r/t for v or dr/dt?

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SUMMARY

The discussion centers on the definitions and applications of kinematic quantities, specifically the relationship between velocity, displacement, and time. The equation in question is v = ωr√(m_b/m_s), where the user contemplates substituting r/t for v to solve for time. The confusion arises from the distinction between average velocity (r/t) and instantaneous velocity (dr/dt). The user seeks clarity on the validity of this substitution and the dependencies of the variables on time, including whether r and ω are functions of time and the role of acceleration.

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  • Kinematics principles, including definitions of velocity and acceleration
  • Understanding of instantaneous vs. average rates of change
  • Familiarity with the equation v = ωr√(m_b/m_s)
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Mr Davis 97
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I am a little confused about how we define the kinematic quantities that are rates. What is velocity defined as? Is it the instantaneous time rate of change of displacement, or is it simply displacement divided by time? Here is an example of where this problem comes up:

I need to solve the equation ##\displaystyle v = \omega r \sqrt{\frac{m_b}{m_s}}## for time. The only way I see of doing this is substituting ##\displaystyle \frac{r}{t}## for ##\displaystyle v## in order to cancel the two r's and solve for time. However, what gives me the right to make this substitution? Isn't ##\displaystyle \frac{r}{t}## just the average velocity, while ##\displaystyle \frac{dr}{dt}## is the instantaneous velocity? Why am I able to choose either or solely for my purposes at hand?
 
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What is the actual problem and how these quantities depend on time? Is r a function of time? is omega a function of time?
 
Is there acceleration involved?
 

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