Subtracting AC Voltages for Audio Amp Simulation

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The discussion focuses on calculating the difference in input voltages V2 and V3 for a basic audio amplifier simulation in LTspice. The user is attempting to verify their calculations for the output current IC1, which they have computed as 3.5 microamps, leading to a voltage difference V(2,3) of 0.000365 amps. They receive guidance on how to measure the differential voltage in LTspice, which results in a value of 42.5 microvolts peak-to-peak. The user expresses confusion over the units and discrepancies in their calculations compared to LTspice's output of 7.2 microamps peak-to-peak. The conversation highlights the importance of accurate voltage and current measurements in amplifier simulations.
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Subtracting input voltages input to long tail pair
I am studying the calculations made for small signal amplification with in the web article http://www.ecircuitcenter.com/Circuits_Audio_Amp/Basic_Amplifier/Basic_Audio_Amplifier.htm.
I have created the simulation for the basic amplifier in Ltspice (attached)
I'm having a problem finding the calculating the difference in the input voltages, V2 and V3 to verify the equation
ic1 = vin · 1/2 · gm1 = vin · 1/2 · 0.0192 = vin · 0.0096 (A/V)

My calculations so far give a value for IC1 as 3.5 microamps which would point to a value of V(2,3) as 0.000365 amps.
Please help me to prove this value correct?
 
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PS how do i attach a Ltspice asc file, the forum won't allow me?
 
ntetlow said:
PS how do i attach a Ltspice asc file, the forum won't allow me?
Rename it .txt and mention in the text of your post that it needs to be changed back to .asc to run it in LTSpice.
 
berkeman said:
Rename it .txt and mention in the text of your post that it needs to be changed back to .asc to run it in LTSpice.
this is an asc file
 

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That works.
Label your nodes 2 and 3.
To measure differential voltage from 2 to 3, run, then click and drag node 2 to node 3.
Zoom the plot window, that will give you; V(2,3) = 42.5 uV Vpp.

ntetlow said:
My calculations so far give a value for IC1 as 3.5 microamps which would point to a value of V(2,3) as 0.000365 amps.
Please help me to prove this value correct?
A voltage V(2,3) cannot have the unit amps.
 
Thank you. I didn't know you could do that to get the voltage difference.
According to the above equation stated (ic1 = vin · 1/2 · gm1 = vin · 1/2 · 0.0192 = vin · 0.0096 (A/V))
then ic1 should equal 42.5uV pp X 0.0096 which gives 4.08E-7V.
Looking at ltspice it is showing as 7.2uA pp, what do you think?
 
Thank you. I didn't know you could do that to get the voltage difference. According to the above equation stated (ic1 = vin · 1/2 · gm1 = vin · 1/2 · 0.0192 = vin · 0.0096 (A/V)) then ic1 should equal 42.5uV pp X 0.0096 which gives 4.08E-7V. Looking at ltspice it is showing as 7.2uA pp, what do you think?

Reference: https://www.physicsforums.com/threads/subtract-ac-voltages.1015880/
 
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