Femme_physics
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Electronic circuit with Op-Amp, Switch and Diodes
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No. Both wrong!
You fixed some errors, but introduced more. You keep jumping ahead before your error is sorted out.
Look what you've done to the inputs: you have current going the wrong way from the battery. Current should enter the external circuit from the long side (+) of the cell symbol.
You fixed some errors, but introduced more. You keep jumping ahead before your error is sorted out.
Look what you've done to the inputs: you have current going the wrong way from the battery. Current should enter the external circuit from the long side (+) of the cell symbol.
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Let's go back to the sketches here, and just focus on the top one https://www.physicsforums.com/showpost.php?p=3792186&postcount=22
No need for any more sketches. You correctly figured out which diode is conducting. So you know that the circuit is operating, you just need to account for why it does.
No need for any more sketches. You correctly figured out which diode is conducting. So you know that the circuit is operating, you just need to account for why it does.
Femme_physics
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Because there's voltage?
That's because it's an inverter
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Femme_physics said:
Uhh
?Current flows from + to -.
So it (almost) always flows away from the plus pole of a battery (the long line) and it (almost) always flows toward the minus pole of a battery (short line).
Certainly in this case it does.
However, in some of your drawings it does, but in others it doesn't...
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Femme_physics
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http://img535.imageshack.us/img535/5793/t2774.gif
Tiny discordant note is your comment "L1 lights more brightly". Why?
Tiny discordant note is your comment "L1 lights more brightly". Why?
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Femme_physics
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Because it has more current going through it?
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Hmmm <checking back sees they have different resistances>. Quite right!Femme_physics said:
Well, almost certainly right. Providing they have equal voltage ratings, the higher current one should be brighter.
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Femme_physics said:
Yep. :)