Calculating Unknown Voltages on Op Amp Circuits

  • Thread starter Thread starter j172
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around calculating unknown voltages in operational amplifier (op amp) circuits, focusing on various configurations such as inverting, summing, non-inverting, and current-to-voltage setups. Participants are seeking guidance on specific calculations and the application of relevant equations in their homework problem.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant outlines their calculations for different op amp configurations, indicating struggles particularly with the summing configuration.
  • Another participant notes that the voltage at both inputs of the op amp is equal and at ground for the inverting configuration.
  • There is a correction regarding the resistance values used in the calculations, with a suggestion that R's cancel in the summing configuration.
  • Some participants express confusion about how to isolate the unknown voltage in the summing configuration, questioning if transposition is necessary.
  • One participant asserts that the value for the unknown voltage in the summing configuration is 1/2 volt, suggesting verification by substituting back into the original equation.

Areas of Agreement / Disagreement

Participants exhibit a mix of agreement and disagreement, particularly regarding the calculations and the approach to isolating the unknown voltage in the summing configuration. There is no consensus on the method to proceed with the calculations.

Contextual Notes

Some participants express uncertainty about the assumptions made in the calculations, particularly regarding the values of resistances and the implications of ideal op amps. The discussion reflects a variety of interpretations of the equations involved.

j172
Messages
2
Reaction score
0
Poster has been reminded to post schoolwork in the Homework Help forums (moved from EE)
Hi everybody!

This is my first post as I am needing some help in a question I am struggling with. Not looking for answers, just some guidance in the right direction.

Homework Statement


[/B]
I need to calculate the unknown, highlighted, voltages on the op amp circuits (attached).

Assume all op-amps are ideal

Homework Equations



See below

The Attempt at a Solution



I have done the following so far:

a) Inverting
A=-Rf/Ri =(-100)/10=-10
Vi =I1*R1 =0.00001*100000=1 V
Vo=(-Rf/Ri )*Vi
Vo =1*-10
Vo =-10 V

b) Summing
Vo=-(Rf/R_1 V_1+Rf/R_2 V_2 )
-2=(Rf/R_1 1+Rf/(R/2) V_2 )

c) Non-inverting
V1 =V2
V1 =100 mV
V2 =100 mV

d) Current to Voltage
Vo=-I1*Rf
Vo =-0.0002*10000=-2
Vo =-2 V

I am struggling the (b). I can't see how to calculate given only one value, and also with (c)

Many thanks in advance, happy to discuss the methods.

Joel
 

Attachments

  • Op Amps Question.png
    Op Amps Question.png
    16.6 KB · Views: 578
Last edited:
Physics news on Phys.org
For A, Note that the voltage at both inputs to the op amp are equal, and at ground.
For B, I have 1R-2R+x(R/2)=0
For C & D, we agree.
 
j172 said:
a) Inverting
A=-Rf/Ri =(-100)/10=-10
Vi =I1*R1 =0.00001*100000=1 V
You have R1 wrong.
b) Summing
Vo=-(Rf/R V_1+Rf/R_2 V_2 )
-2=(Rf/R 1+Rf/(R/2) V_2 )
correct (I took out the "Rf" , should be just "R" everywhere)
c) Non-inverting
V1 =V2
V1 =100 mV
V2 =100 mV
Right.
d) Current to Voltage
Vo=-I1*Rf
Vo =-0.0002*10000=-2
Vo =-2 V
Right
I am struggling the (b). I can't see how to calculate given only one value, and also with (c)
The R's cancel. There is nothing more to do with (c) than you have already done.
 
  • Like
Likes   Reactions: j172
Thank you very much for your help
 
b) Summing
Vo=-(R/R*V_1+R/R*V_2 )
-2=(R/R*1+R/(R/2)*V_2 )

So is there another step to this because this equation doesn't give V_2. do you transpose it ?
 
Last edited:
rob1985 said:
b) Summing
-2=(R/R*1+R/(R/2)*V_2 )
So is there another step to this because this equation doesn't give V_2. do you transpose it ?
It doesn't?
 
can you elaborate please
 
rob1985 said:
can you elaborate please
Well let's see - you have one equation with 1 unknown.
If this is difficult I really am at a loss as to what to hint next, so I must perforce cease from further such.
 
b is 1/2 volt
 
  • #10
rob1985 said:
b is 1/2 volt
As a check, substitute your answer into the original equation to ensure that your answer does indeed make both sides of the equation equal.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
Replies
15
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
34
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
21
Views
3K