MHB Subtracting mixed fractions help

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To subtract mixed fractions, convert them to improper fractions first. The example given is four and five-ninths minus two-thirds, which is calculated as 41/9 minus 2/3. Finding a common denominator leads to 41/9 minus 6/9, resulting in 35/9. This improper fraction can then be converted back to a mixed fraction, yielding three and eight-ninths as the final answer. The steps demonstrate the process of subtraction and conversion clearly.
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Hi, I'm new. Please bear with me because I'm not familiar with the code of this forum.

I don't know how to enter a mixed fraction correctly, so I'm just going to write it out. Here is the problem:

Four and five-ninths minus 2/3

Can someone explain to me why the answer is three and eight-ninths? I know that's the answer because the textbook I'm using says so, but I haven't been able to figure out why.
 
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I would convert to improper fractions:

$4\frac{5}{9}-\dfrac{2}{3}=\dfrac{9\cdot4+5}{9}-\dfrac{2}{3}=\dfrac{41}{9}-\dfrac{2}{3}$

Now, get a common denominator:

$$\frac{41}{9}-\frac{2}{3}\cdot\frac{3}{3}=\frac{41}{9}-\frac{6}{9}=\frac{41-6}{9}=\frac{35}{9}$$

Now express as a mixed fraction:

$\dfrac{35}{9}=\dfrac{3\cdot9+8}{9}=3+\dfrac{8}{9}=3\frac{8}{9}$

Does that make sense?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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