High School Summation Rules: What Happens When k=0?

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SUMMARY

The discussion clarifies the summation rules for constant values, specifically addressing the case when the lower bound of the summation index is zero. It establishes that the sum of a constant, such as 3, from k=0 to n results in 3(n+1). Additionally, it confirms that the lower bound does not affect the total count of terms, as illustrated by the example of summing from k=-1, which yields 3(n+2). The general formula for summation is succinctly summarized as ∑k=ab c = c (b-a+1).

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n
∑ 3
k=0

How does this make sense when k=0?
 
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The sum is ##3+3+...=3(n+1)##
 
Gene Naden said:
The sum is ##3+3+...=3(n+1)##
Oh okay. The lower bound is the index origin and doesn't matter if it is negative?
n
∑ 3
k=-1
3+3+...=3(n+2)
 
Correct!
 
To summarise,
$$
\sum_{k=a}^{b} c = c (b-a+1)
$$
for constant ##c##.
 
DrClaude said:
To summarise,
$$
\sum_{k=a}^{b} c = c (b-a+1)
$$
for constant ##c##.
i.e. one is counting fence posts, not sections of wire.
 

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